[英]Selecting records from a table not in another table
I have two tables. 我有两张桌子。
Course
course_id | name
------------------
1 | PROG
2 | ENGL
3 | SCIE
Enrollment List
ID | student_id | course_id | grade
-----------------------------------
1 | 445566 | 1 | 4.0
2 | 445566 | 2 | 2.0
3 | 778899 | 3 | 2.5
I need to query the tables such that it returns the student_id and the courses they haven't taken yet. 我需要查询表,以便它返回student_id和他们尚未学习的课程。 Outcome should be:
结果应该是:
student_id | course_id
----------------------
445566 | 3
778899 | 1
778899 | 2
I tried the query 我试过了这个问题
SELECT student_id, name FROM course c, list l WHERE NOT EXISTS(SELECT NULL FROM course c, list l WHERE c.course_id=l.course_id)
which returned zero records. 返回零记录。 How would I do this?
我该怎么做?
Simple rule: Never use commas in the FROM
clause. 简单规则: 永远不要在
FROM
子句中使用逗号。 Always use explicit JOIN
syntax. 始终使用显式
JOIN
语法。
In any case, you need to approach this in a particular way. 无论如何,您需要以特定方式处理此问题。 Start with a list of all students and all courses.
从所有学生和所有课程的列表开始。 Then use
left join
or not exists
to filter out the ones that are not in the list: 然后使用
left join
或not exists
来过滤掉不在列表中的连接:
SELECT s.student_id, c.name
FROM course c CROSS JOIN
(SELECT DISTINCT student_id FROM list l) s
WHERE NOT EXISTS (SELECT 1
FROM list l2
WHERE c.course_id = l2.course_id and s.student_id = l2.student_id
)
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