在Groovy中将String转换为arrayList

Question

I have a string like: String str = "[aa,bb,cc,dd]" . I want to convert this to a list in groovy like [aa, bb, cc, dd] . Any groovy method available for this type conversion?

Answer 1

Using regexp replaceAll

String str = "[aa,bb,cc,dd]"
def a = str.replaceAll(~/^\[|\]$/, '').split(',')
assert a == ['aa', 'bb', 'cc', 'dd']

EDIT:

The following version is a bit more verbose but handles extra white spaces

String str = " [ aa , bb , cc , dd ] "
def a = str.trim().replaceAll(~/^\[|\]$/, '').split(',').collect{ it.trim()}
assert a == ['aa', 'bb', 'cc', 'dd']

Answer 2

You should try as below :-

String str = "[aa,bb,cc,dd]"
assert str[1..str.length()-2].tokenize(',') == ['aa', 'bb', 'cc', 'dd']

Hope it helps..:)

Answer 3

Here you go:

String str= "['aa', 'bb', 'cc', 'dd']"
assert Eval.me(str) == ['aa', 'bb', 'cc', 'dd']

Eval is what you need.

Answer 4

another way w/o replaceAll & tokenize:

def s = '[aa,bb,cc,dd]'
def a = []
s.eachMatch( /[\[]?([^\[\],]+)[,\]]?/ ){ a << it[ 1 ] }
assert '[aa, bb, cc, dd]' == a.toString()