[英]how to populate a drop down list from my SQL database using php
i want to populate a drop down list from my sql database using php, but it shows the below error: 我想使用php从我的sql数据库填充一个下拉列表,但显示以下错误:
"Warning: mysql_fetch_array() expects parameter 1 to be resource, object given in C:\\wamp\\www\\Q&A\\signup.php on line 43"
“警告:mysql_fetch_array()期望参数1为资源,第43行的C:\\ wamp \\ www \\ Q&A \\ signup.php中给出的对象”
my code is: 我的代码是:
<?php
$sql = "SELECT category_name FROM category ORDER BY RAND() LIMIT 1";
$result=mysqli_query($conn, $sql) or die ("Query to get data from category failed: ".mysql_error());
while ($row = mysql_fetch_array($result)) {
$category_name=$row["category_name"];
echo "<option>" . $category_name . "</option>";
}
?>
It's because you're using old function mysql_fetch_array
it should be mysqli_fetch_array
. 这是因为您正在使用旧函数
mysql_fetch_array
所以它应该是mysqli_fetch_array
。
Also mysql_error
should be mysqli_error
which accepts connection as single parameter. 另外
mysql_error
应该是mysqli_error
,它接受连接作为单个参数。
Update your code like this, 像这样更新您的代码,
<?php
$sql = "SELECT category_name FROM category ORDER BY RAND() LIMIT 1";
$result=mysqli_query($conn, $sql) or die ("Query to get data from category failed: ".mysqli_error(conn));
while ($row = mysqli_fetch_array($result)) {
$category_name=$row["category_name"];
echo "<option>" . $category_name . "</option>";
}
?>
I'm assuming you've a valid connection to the database in $conn
variable. 我假设您在
$conn
变量中具有到数据库的有效连接。
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