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从JSON检索结果到ArrayList

[英]Retrieving result from JSON to ArrayList

I have the following JSON- 我有以下JSON- 在此处输入图片说明

  1. journeys 旅程
    • {obj} 0
      • [ ] legs []腿
        • {obj} 0 {obj} 0
          • {obj} instruction {obj}指令
          • "string" detailed : string value goes here0 详细的“字符串”:字符串值在这里0
        • {obj} 1 {obj} 1
          • {obj} instruction {obj}指令
          • "string" detailed : string value goes here1 详细的“字符串”:字符串值在此处1
    • {obj} 1
      • [ ] legs []腿
        • {obj} 0 {obj} 0
          • {obj} instruction {obj}指令
          • "string" detailed : string value goes here0 详细的“字符串”:字符串值在这里0
        • {obj} 1 {obj} 1
          • {obj} instruction {obj}指令
          • "string" detailed : string value goes here1 详细的“字符串”:字符串值在此处1
    • {obj} 2
      • [ ] legs []腿
        • {obj} 0 {obj} 0
          • {obj} instruction {obj}指令
          • "string" detailed : string value goes here0 详细的“字符串”:字符串值在这里0
        • {obj} 1 {obj} 1
          • {obj} instruction {obj}指令
          • "string" detailed : string value goes here1 详细的“字符串”:字符串值在此处1

My plan is to iterate through values "journeys" and store them in an ArrayList . 我的计划是遍历值“旅程”并将它们存储在ArrayList Similarly, store "legs" in another ArrayList and finally get retrieve the value for the object instruction . 同样,将“腿”存储在另一个ArrayList ,最后获取检索对象instruction的值。 As you can see parent journeys has 3 child {obj} 0 , {obj} 1 , {obj} 2 . 如您所见,父journeys有3个孩子{obj} 0{obj} 1{obj} 2 I can get the journeys stored using -- 我可以使用以下方式存储journeys

ArrayList<JSONObject> journey = new ArrayList<>();
ArrayList<JSONArray> leg = new ArrayList<>();
ArrayList<JSONObject> legDetails = new ArrayList<>();

try {
            JSONArray jArray = object.getJSONArray("journeys");
            if (jArray != null) {
                for (int i=0;i<jArray.length();i++){
                    journey.add(jArray.getJSONObject(i));
                }
                if (!journey.isEmpty()){
                    for (int j=0;j<journey.size();j++){
                         leg.add(journey.get(j).getJSONArray("legs"));
                }
            }
            if (!leg.isEmpty()){
                for (int i = 0; i<leg.size();i++){
                     legDetails.add(leg.get(i).getJSONObject(i));
                    }
            }
          }
        } 
        catch (JSONException e) {
            e.printStackTrace();
        }

Now each journey returns 2 legs and the number changes time to time. 现在,每次旅程都会返回2条腿,并且数字会不时变化。 I was expecting 6 JSONObject at the end of last for loop but I only get 2 and a out of range exception. 我在last for循环的末尾期望6 JSONObject ,但是我只得到2和一个超出范围的异常。

Things to remember: Journey has Routes (Obj 0,1,2). 要记住的事情:旅途有路线(Obj 0,1,2)。 Routes has legs (Obj 0,1). 路线有支腿(Obj 0,1)。 Legs consists of instruction with detail string. 腿由带detail字符串的instruction组成。

Is this right approach to retrieve the value? 这是获取价值的正确方法吗? and what am I doing wrong? 我在做什么错?

problem is here 问题在这里

        if (!journey.isEmpty()){

          for (int j=0;j<journey.size();j++){
                   leg.add(journey.get(j).getJSONArray("legs"));

                }

        }

journery's have 3 objects. 旅程有3个对象。

for j=0 you add journey[0] array to leg
for j=1 you add journey[1] array to leg
for j=2 you add journey[2] array to leg

so legs will have 3 arrays. 所以腿将有3个阵列。

if (!leg.isEmpty()){
   for (int i = 0; i<leg.size();i++){
      legDetails.add(leg.get(i).getJSONObject(i));
   }
}

here leg.size()=3; 在这里leg.size()= 3;

for i=0 it will add leg[0]'s [0]th element
for i=1 it will add leg[1]'s [1]th element
for i=2 it will add leg[2]'s [2]th element (this is out of range)

update :: 更新::

if (!leg.isEmpty()){
   for (int i = 0; i<leg.size();i++){
      for(int j=0;j<leg.get(i).size();j++)
         legDetails.add(leg.get(i).getJSONObject(j));
   }
}

This should help 这应该有帮助

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