从多列文件中提取行

Question

I have the following format of data set:

Identified_____ID#2357_____ReadSequence:1238  
Unknown_____0_____ReadSequence:0979  
Unknown_____0_____ReadSequence:5476  
Identified_____ID#567899_____ReadSequence:4376  

Using awk command, how can I extract the ReadSequences but only lines which have been identified (based on the first column entries)?

Answer 1

$ awk -F"_____" '$1=="Identified" {print $3}' test.in 
ReadSequence:1238
ReadSequence:4376

If you only want the ReadSequence ids, gsub is your friend:

$ awk -F"_____" '$1=="Identified" {gsub(/^.*:/,"",$3); print $3}' test.in 
1238
4376 

Answer 2

awk -F'_____' '/^Identified/ {print $NF}' file
ReadSequence:1238
ReadSequence:4376

OR

awk '/^Identified/ {split($0,a,"_____");print a[3]}' info
ReadSequence:1238
ReadSequence:4376

OR if you only want to read the value of ReadSequence then

awk -F'_____' '/^Identified/ {split($NF,a,":"); print a[2]}' file
1238
4376

Answer 3

$ awk -F':' '/^Identified/{print $NF}' file
1238
4376