[英]New to structs, how come my program is not running?
The program asks the user for a numerator and denominator in the enter function, then it needs to simplify and then display it. 该程序在输入功能中要求用户提供分子和分母,然后需要进行简化然后显示。 I tried running it and my program broke.
我尝试运行它,但程序中断了。
Any tips on how to do this? 有关如何执行此操作的任何提示?
I am still trying to learn how to do structures. 我仍在尝试学习如何做结构。
#define _CRT_SECURE_NO_WARNINGS
#include <stdio.h>
struct Fraction
{
int numerator;
int denominator;
};
void enter(struct Fraction *choice)
{
printf("Numerator: \n");
scanf("%d", choice->numerator);
printf("Denominator: \n");
scanf("%d", choice->denominator);
}
void simplify(struct Fraction *reduce)
{
reduce->numerator = reduce->numerator / reduce->numerator;
reduce->denominator = reduce->denominator / reduce->denominator;
}
void display(const struct Fraction *show)
{
printf("%d / %d", show->numerator, show->denominator);
}
int main(void)
{
struct Fraction f;
printf("Fraction Simplifier\n");
printf("===================\n");
enter(&f);
simplify(&f);
display(&f);
}
Problem 1 问题1
The lines 线
scanf("%d", choice->numerator);
scanf("%d", choice->denominator);
need to be: 需要:
scanf("%d", &choice->numerator);
scanf("%d", &choice->denominator);
// ^^ Missing
Problem 2 问题2
The following lines: 以下几行:
reduce->numerator = reduce->numerator / reduce->numerator;
reduce->denominator = reduce->denominator / reduce->denominator;
are equivalent to: 等效于:
reduce->numerator = 1.0;
reduce->denominator = 1.0;
You need code to compute the GCD of the numerator and denominator and then use: 您需要代码来计算分子和分母的GCD,然后使用:
double gcd = get_gcd(reduce->numerator, reduce->denominator);
reduce->numerator = reduce->numerator/gcd;
reduce->denominator = reduce->denominator/gcd;
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