String.contains找到一个子字符串但不是Pattern.matches？

Question

In one of my try/catch blocks, I catch an exception e , and this:

e.toString().contains("this is a substring") returns true

while

Pattern.matches(".*this is a substring.*", e.toString()) returns false

Why does this happen? Including the .* as the prefix and suffix for the regex pattern should essentially make these two functions do the same thing right?

Answer 1

If your input string contains newline symbol(s), .* is not enough in .matches() that requires a full string match.

Thus, you need a DOTALL modifier:

Pattern.matches("(?s).*this is a substring.*", e.toString())
                 ^^^^ 

See the Java regex reference :

In dotall mode, the expression . matches any character, including a line terminator. By default this expression does not match line terminators.

Dotall mode can also be enabled via the embedded flag expression (?s) . (The s is a mnemonic for "single-line" mode, which is what this is called in Perl.)

NOTE : if you need to check the presence of a literal substring inside a longer string, a .contains() method should work faster. Or, if you need a case insensitive contains , you may also check StringUtils.containsIgnoreCase .