[英]changing the format of a arbitrary date in php
I have a program where I want to enter an arbitrary date 我有一个想要输入任意日期的程序
2016-07-21 00:00:00
and I want to convert the format of the date to July 21 2016 00:00 GMT. 我想将日期格式转换为2016年7月21日格林尼治标准时间。
I started to write the following code in php: 我开始在php中编写以下代码:
#!/bin/php
<?php
$date = "2016-07-21 00:00:00";
echo date_format($date, 'F jS Y H:i:s');
?>
Now when I try to use this code, which I got from http://php.net/manual/en/function.date.php I get the following error messages: 现在,当我尝试使用从http://php.net/manual/en/function.date.php获得的这段代码时,收到以下错误消息:
PHP Warning: date_format() expects parameter 1 to be DateTime, string given in /home/vrsops/server/work/experimental/exp.php on line 8
What does this mean? 这是什么意思? How do I resolve this issue and be able to convert the date format to the one specified above?
如何解决此问题并能够将日期格式转换为上面指定的格式?
As the error message states date_format()
requires a DateTime()
object to be formatted. 由于错误消息指出
date_format()
需要格式化DateTime()
对象。 You gave it a string. 您给了它一个字符串。 If you want to use
date_format()
then you need to create use date_create()
to create a DateTime()
object. 如果要使用
date_format()
则需要创建使用date_create()
来创建DateTime()
对象。
<?php
$date = date_create("2016-07-21 00:00:00");
echo date_format($date, 'F jS Y H:i:s');
?>
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