[英]How can you multiply numbers in string in C++?
I misunderstood my homework assignment so I am trying to fix it. 我误解了我的作业,所以我试图解决它。 Here is the assignment
这是作业
-- For a two lap race, calculate the race time. -对于两圈比赛,计算比赛时间。 To do that, you would need to multiply the user input of lap time and multiply it by 2 to get race time.
为此,您需要将用户输入的单圈时间乘以2,以获得比赛时间。
Is it possible to do it in string? 可以用字符串做吗?
Here is a sample of what I have so far. 这是我到目前为止的样本。 Please disregard
race_time
variable description. 请忽略
race_time
变量描述。 I thought race time and lap time were the same, but they are not. 我以为比赛时间和单圈时间是相同的,但事实并非如此。 I want to do something like...
我想做类似...
race_time1 * 2
to obtain the race time result as the output. 获得比赛时间结果作为输出。
#include <iostream>
using std::cout;
using std::cin;
using std::endl;
#include <string>
using std::string;
int main(){
string car_number1;
string car_number2;
string car_number3;
string car_color1;
string car_color2;
string car_color3;
string race_time1;
string race_time2;
string race_time3;
cout<<"We are doing a 2 lap race." << ' ' ;
//Data for car 1
cout<<"Enter a number for the first race car: ";
cin>>car_number1;
cin.ignore();
cout<<"Enter a color for car number " << car_number1 << endl;
getline(cin,car_color1);
cout<<"Enter a lap time in MM:SS: for the " << car_color1 <<' '<< car_number1 << ' '<< "car" << endl;
getline(cin,race_time1);
cout<<"You have entered a"<<' '<< car_number1<<' '<<car_color1<<' '<< "car with a lap time of" << ' ' << race_time1 <<endl;
Classic class operator overloading and class definition, I am sure you might have lot of doubts. 经典的类运算符重载和类定义,我相信您可能会有很多疑问。 Why so complex but there are lot of details and simplicity of use involved in it.
为什么这么复杂,却涉及到许多细节和使用的简便性。
// Test1.cpp : Defines the entry point for the console application.
//
#include "stdafx.h"
#include <iostream>
#include <string>
#include <sstream>
using namespace std;
// Lap_time class represents minutes and seconds
struct lap_time {
int minutes;
int seconds;
// Default constructors
lap_time() : minutes(0),seconds(0) { }
lap_time(const string& str) {
stringstream ss(str);
string value;
if (std::getline(ss, value, ':'))
minutes = stoi(value);
if (std::getline(ss, value, ':'))
seconds = stoi(value);
}
lap_time(int m, int s) : minutes(m), seconds(s) { }
// input operator overload
friend istream& operator >> (istream& is, lap_time&);
// output operator overload
friend ostream& operator << (ostream& os, lap_time&);
// Time multiply operation
lap_time operator*(const int& x) {
int time = (this->minutes) * 60 + this->seconds;
time = time * 2;
return lap_time(time / 60, time % 60);
}
};
// input operator overload declaration
istream& operator>>(istream& is, lap_time& lt)
{
string laptime;
is >> laptime;
stringstream ss(laptime);
string value;
if (std::getline(ss, value, ':'))
lt.minutes = stoi(value);
if (std::getline(ss, value, ':'))
lt.seconds = stoi(value);
return is;
}
// ouput operator overload declaration
ostream& operator<<(ostream& os, lap_time& lt)
{
stringstream ss;
ss << lt.minutes << ":" << lt.seconds;
os << ss.str();
return os;
}
// getline function overload to read lap_time
void getline(std::istream& is, lap_time& lt)
{
string laptime;
is >> laptime;
stringstream ss(laptime);
string value;
if (std::getline(ss, value, ':'))
lt.minutes = stoi(value);
if (std::getline(ss, value, ':'))
lt.seconds = stoi(value);
}
int main()
{
string car_number1;
string car_number2;
string car_number3;
string car_color1;
string car_color2;
string car_color3;
lap_time race_time1;
lap_time race_time2;
lap_time race_time3;
cout << "We are doing a 2 lap race." << ' ' << endl;
//Data for car 1
cout << "Enter a number for the first race car: " << endl;
cin >> car_number1;
cin.ignore();
cout << "Enter a color for car number " << car_number1 << endl;
getline(cin, car_color1);
cout << "Enter a lap time in MM:SS: for the " << car_color1 << ' ' << car_number1 << ' ' << "car" << endl;
getline(cin, race_time1);
cout << "Single Lap race time is :" << race_time1 << endl;
// I do not think you should multiply by two unless assuming both laps equal timing.
cout << "Two lap race time is : " << (race_time1 * 2) << endl;
}
You could use function like this: 您可以使用如下功能:
template<typename IntFunction>
std::string transform_numbers_in_string(std::string text, IntFunction func)
{
auto cond = [](auto& x) {return std::isdigit(x);};
for (auto it = std::find_if(text.begin(), text.end(), cond);
it != text.end();
it = std::find_if(it, text.end(), cond))
{
std::string before, after;
auto pos = it - text.begin();
std::size_t i;
for(i=0; cond(*(it+i)); ++i)
before += *(it+i);
after = std::to_string(func(std::atoll(before.c_str())));
text.replace(pos, i, after);
it = text.begin() + pos + after.size();
}
return text;
}
Example program: 示例程序:
int main()
{
auto lambda1 = [](const auto& x) {return x*2;};
auto lambda2 = [](const auto& x) {return x*x;};
auto lambda3 = [](const auto& ) {return 666;};
std::string text {"I have 3 dogs and 4 cats and 5 hamsters."};
std::cout << text << std::endl << std::endl;
std::cout << transform_numbers_in_string(text, lambda1) << std::endl;
std::cout << transform_numbers_in_string(text, lambda2) << std::endl;
std::cout << transform_numbers_in_string(text, lambda3) << std::endl;
}
Output: 输出:
I have 3 dogs and 4 cats and 5 hamsters.
I have 6 dogs and 8 cats and 10 hamsters.
I have 9 dogs and 16 cats and 25 hamsters.
I have 666 dogs and 666 cats and 666 hamsters.
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