正则表达式模式以任何顺序匹配字符串

Question

How to find first match of string abc in shuffled order using regex pattern in java?

Example:

input 1: abcbaa
input 2: bcbaaa
input 3: cbaaab

1st match for input 1: baab
1st match for input 2: b aab
1st match for input 3: aabc

Patterns that I've tried that didn't work:

(?:([abc])(?!\\.*]\\1)){3}
(?!(.)\\1)[abc]{3}

The above 2 patterns matches 3 consecutive characters, including duplicate values.
example: bac
expected: aba

(?=.*[abc])(?=.*[abc])(?=.*[abc])

This one matches and empty character in-between each character. ie, string position (0,0), (1,1), (2,2) etc...

Answer 1

Have you tried to look of all the possibilities? Something like this with your example:

(abc|acb|bca|bac|cab|cba)

Answer 2

Maybe you should try this regex:

^(?=[\s\S]*(a)+)(?=[\s\S]*(b)+)(?=[\s\S]*(c)+)[\s\S]*$

Answer 3

(?:a()|b()|c()){3}\1\2\3

The empty groups act like check boxes, so if \1\2\3 matches, each of the letters must have been seen at least once. Since the regex only consumes three characters, you know there's exactly one of each letter.