将模型方法的返回值分配给模型属性

Question

I have a class similar to this:

class X(models.Model):
  def hello(self):
    return "Humpty Dumpty"

  name = (hello,)
  age = models.IntegerField()

now when I run in the console: y.name being y an instance, I get the following:

(property object at 0x0000000004FDCBD8,)

What am I doing wrong here?

I tried using the @property above the method but it didn't work.

I'd like to get "Humpty Dumpty" when I access y.name . So the method would assign it's value to the attribute.

Answer 1

If you just want to get the function called on attribute access, define name as property and provide your function foo to it:

name = property(hello)

This will set the fget inside the property to your function hello .

y = X()
y.name
'Humpty Dumpty'

Take note, there's a pretty good tutorial on descriptors in the Python Official docs.

Answer 2

That's invalid syntax. You need to do something like this:

class X:
  def __init__(self):
      self.name = self.hello()

  def hello(self):
    return "Humpty Dumpty"

test = X()
print(test.name) # prints "Humpty Dumpty"