MySQL的：两个表加总

Question

I'm attempting to join two tables and also get a SUM and flailing badly. I need to get the total commission amounts for each affiliate where affiliate.approved=1 AND order.status=3.

//affiliate table
affiliate_id | firstname | lastname | approved |
     1            joe        shmoe       1
     2           frank       dimag       0
     3            bob        roosky      1

here's the order table

//order
affiliate_id | order_status_id | commission
    1                3              0.20
    1                0              0.30
    2                3              0.10
    3                3              0.25
    1                3              0.25
    2                3              0.15
    2                0              0.20

and here's what I'd like the query to return:

affiliate_id | commission
    1             0.45
    3             0.25

Here is my attempt that doesn't work. It outputs just one line.

 SELECT order.affiliate_id, SUM(order.commission) AS total, affiliate.firstname, affiliate.lastname FROM `order`, `affiliate` WHERE order.order_status_id=3 AND affiliate.approved=1 AND order.affiliate_id = affiliate.affiliate_id ORDER BY total; 

thanks for any help.

Answer 1

You can try this Query for your solution :-

   SELECT order.affiliate_id, SUM(order.commission) AS total,affiliate.firstname,
  affiliate.lastname 
    FROM `order`, `affiliate`
    WHERE order.order_status_id=3 
    AND affiliate.approved=1 
    AND order.affiliate_id = affiliate.affiliate_id 
    GROUP BY order.affiliate_id
    ORDER BY total; 

Answer 2

You've missed GROUP BY , try this:

SELECT 
      `order`.affiliate_id,
      SUM(`order`.commission) AS total,
      affiliate.firstname,
      affiliate.lastname
FROM `order` 
JOIN `affiliate` 
ON `order`.order_status_id = 3 AND affiliate.approved = 1 AND `order`.affiliate_id = affiliate.affiliate_id
GROUP BY `order`.affiliate_id
ORDER BY total;

Demo Here

Answer 3

First: Remove the implicit join syntax. It's confusing.

Second: You needed to group by affiliate_id . Using aggregate function without group by collapses your result set into a single row.

Here's the query using INNER JOIN :

SELECT
    `order`.affiliate_id,
    SUM(`order`.commission) AS total,
    affiliate.firstname,
    affiliate.lastname
FROM `order`
INNER JOIN`affiliate` ON  `order`.affiliate_id = affiliate.affiliate_id
WHERE `order`.order_status_id = 3
AND affiliate.approved = 1
GROUP BY affiliate.affiliate_id
ORDER BY total;

WORKING DEMO

Caution: You have picked one of the reserved words of MySQL as table name ( order ). Be aware to enclose it with (`)backtick always .

_{Just a gentle reminder}

Answer 4

Here is the solution:

select affiliate.affiliate_id,sum(`order`.commission) as total from affiliate left join `order` on affiliate.affiliate_id=`order`.affiliate_id
where affiliate.approved=1 and `order`.order_status_id=3 group by affiliate.affiliate_id

In addition,"order" is a key word of SQL , I recommend you not to use it as a table/column name.