将函数的结果存储为变量

Question

I'm trying to write an RSA code, but I'm having issues with a simple thing. I want to store the result of a function as a variable, twice in Python. This is my code

def random_odd_between(j,k):
    k1 = (k-1)//2
    j1 = j//2
    a1 = int(random()*(k1-j1+1))+j1
    a = 2*a1 +1
    return a

# The list of primes less than 10^6 is given by:
list_of_primes = prime_range(1,10^6)

# Write a function to check if given number is prime:
def check_if_prime(n):
    prime_flag = 1
    for i in list_of_primes:
        checker = n%i
        if checker != 0:
            if (n/i) in ZZ:
                prime_flag = 0
        break
    else:
        prime_flag = 0
        break
    return prime_flag

# Generate random numbers between 6*10^9 and 10^10 until we get a prime.
# Generate two prime numbers between 6*10^9 and 10^10 for p and q
def get_a_prime():
    count = 0
    prime_found = 0
    while prime_found == 0:
        a = random_odd_between(6*10^9,10^10)
        prime_found = check_if_prime(a)
        count = count + 1
# Print a prime you've got:
    print '%i' %a

p = get_a_prime()
q = get_a_prime()
n = p*q

# Let t stand for totient

t = (p-1)*(q-1)

I can't get my p and q to be defined however, they keep just giving me an error. I realize I need to do some kind of return, but I can't get the syntax right

Answer 1

只需将print '%i' %a替换为return a

Answer 2

I believe you had errors in both your check_if_prime and get_a_prime functions. In the former, ZZ is not defined and the first break should be indented one more level and the last one is redundant. Better yet, just return True or False when needed.

In the second function, you need to return the value that is prime rather than just print it.

def check_if_prime(n):
    if n == 2:
        return True  # 2 is a prime.
    if n % 2 == 0 or n <= 1:
        return False  # Anything less than or equal to one is not prime.

    for divisor in xrange(3, int(n ** 0.5) + 1, 2):  # 3, 5, 7, ..., int(SQRT(n)) + 1
        if not n % divisor:  
            return False  # NOT divisible by the divisor.

    return True  # Must be prime.

def get_a_prime():
    prime_found = False
    while not prime_found:
        a = random_odd_between(6 * 10 ^ 9, 10 ^ 10)
        prime_found = check_if_prime(a)
    return a

Testing

primes = [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101]

# Ensure all primes above are prime per our function.
>>> all(check_if_prime(n) for n in primes)
True

# Ensure all numbers in range 0-101 that is not identified as a prime is not a prime.
>>> any(check_if_prime(n) for n in xrange(102) if n not in primes)
False