简体   繁体   English

使用 PHP Html5 流式传输视频

[英]Streaming video with PHP Html5

I have videos on my website, and I would like to display them streming with Php and html5.我的网站上有视频,我想用 Php 和 html5 显示它们。

I tri to follow this tutorial ( http://codesamplez.com/programming/php-html5-video-streaming-tutorial ) of streaming video creation with php class.我尝试遵循本教程( http://codesamplez.com/programming/php-html5-video-streaming-tutorial )使用 php 类创建流式视频。

 <?php /** * Description of VideoStream * * @author Rana * @link http://codesamplez.com/programming/php-html5-video-streaming-tutorial */ class VideoStream { private $path = ""; private $stream = ""; private $buffer = 102400; private $start = -1; private $end = -1; private $size = 0; function __construct($filePath) { $this->path = $filePath; } /** * Open stream */ private function open() { if (!($this->stream = fopen($this->path, 'rb'))) { die('Could not open stream for reading'); } } /** * Set proper header to serve the video content */ private function setHeader() { ob_get_clean(); header("Content-Type: video/mp4"); header("Cache-Control: max-age=2592000, public"); header("Expires: ".gmdate('D, d MYH:i:s', time()+2592000) . ' GMT'); header("Last-Modified: ".gmdate('D, d MYH:i:s', @filemtime($this->path)) . ' GMT' ); $this->start = 0; $this->size = filesize($this->path); $this->end = $this->size - 1; header("Accept-Ranges: 0-".$this->end); if (isset($_SERVER['HTTP_RANGE'])) { $c_start = $this->start; $c_end = $this->end; list(, $range) = explode('=', $_SERVER['HTTP_RANGE'], 2); if (strpos($range, ',') !== false) { header('HTTP/1.1 416 Requested Range Not Satisfiable'); header("Content-Range: bytes $this->start-$this->end/$this->size"); exit; } if ($range == '-') { $c_start = $this->size - substr($range, 1); }else{ $range = explode('-', $range); $c_start = $range[0]; $c_end = (isset($range[1]) && is_numeric($range[1])) ? $range[1] : $c_end; } $c_end = ($c_end > $this->end) ? $this->end : $c_end; if ($c_start > $c_end || $c_start > $this->size - 1 || $c_end >= $this->size) { header('HTTP/1.1 416 Requested Range Not Satisfiable'); header("Content-Range: bytes $this->start-$this->end/$this->size"); exit; } $this->start = $c_start; $this->end = $c_end; $length = $this->end - $this->start + 1; fseek($this->stream, $this->start); header('HTTP/1.1 206 Partial Content'); header("Content-Length: ".$length); header("Content-Range: bytes $this->start-$this->end/".$this->size); } else { header("Content-Length: ".$this->size); } } /** * close curretly opened stream */ private function end() { fclose($this->stream); exit; } /** * perform the streaming of calculated range */ private function stream() { $i = $this->start; set_time_limit(0); while(!feof($this->stream) && $i <= $this->end) { $bytesToRead = $this->buffer; if(($i+$bytesToRead) > $this->end) { $bytesToRead = $this->end - $i + 1; } $data = fread($this->stream, $bytesToRead); echo $data; flush(); $i += $bytesToRead; } } /** * Start streaming video content */ function start() { $this->open(); $this->setHeader(); $this->stream(); $this->end(); } }

So i have two problems :所以我有两个问题:

1 - I am also trying to stream to a player but the video is taking over my whole page how do i make the video is just added to my html5 player. 1 - 我也在尝试流式传输到播放器,但视频占据了我的整个页面,我该如何将视频添加到我的 html5 播放器中。

2 - when I make a url http video ( http://video.newsmed.fr/pdv/0616.mp4 ) that does not work 2 - 当我制作一个无效的 url http 视频 ( http://video.newsmed.fr/pdv/0616.mp4 ) 时

Thanks to help me solve this problem or suggest me other solutions php.感谢帮助我解决这个问题或建议我其他解决方案 php.ini 。

  1. I am also trying to stream to a player but the video is taking over my whole >page how do i make the video is just added to my html5 player.我也在尝试流式传输到播放器,但视频正在接管我的整个 > 页面,如何将视频添加到我的 html5 播放器中。

Did you just copy the HTML example without changing a thing?您是否只是复制了 HTML 示例而没有更改任何内容? look at the HTML5 example, you will see that theres width="100%", you can change the value to your fit.看一下 HTML5 示例,您会看到有 width="100%",您可以将值更改为适合您的值。

2 - when I make a url http video ( http://video.newsmed.fr/pdv/0616.mp4 ) that does >not work 2 - 当我制作一个 url http 视频 ( http://video.newsmed.fr/pdv/0616.mp4 ) 时 > 不起作用

the URL should point to your php code, not the video file path. URL 应该指向您的 php 代码,而不是视频文件路径。 for example: yourdomain.com/dir/your-php-file.php?video=0616.mp4例如:yourdomain.com/dir/your-php-file.php?video=0616.mp4

try to put your-php-file.php code instead of the videostream.php class on your question.尝试将 your-php-file.php 代码而不是 videostream.php 类放在您的问题上。

try insert on up to class on top尝试插入到最上面的班级

$stream = new VideoStream("file.mp4 or www//file.mp4");
$stream->start();exit;

So here is my html所以这是我的 html

<a href="#" onclick="play_video(event,`<?PHP echo $video_url?>`)">
<video  style="height:100%;width:100%" controls autoplay >
                    <source src="" type="video/mp4" id='video_player'>   
                </video>

and then use the below jQuery然后使用下面的jQuery

<script>
    var play_video;
    $(document).ready(function(){

        play_video=function(event,video_url){
            event.preventDefault();
            console.log("play video");
            $('#video_player').attr('src',`index.php?action=play_video&file_path=${video_url}`);
        };

    });
    </script>

and here is your index.php这是你的 index.php

<?php
include "../util/VideoStream.php";

$action = filter_input(INPUT_POST, 'action');
if ($action === NULL) {
    $action = filter_input(INPUT_GET, 'action');
    if ($action === NULL) {
        $action = 'play_video';
    }
} else {
    $action = trim(strtolower($action));
}

switch ($action) {

    case 'play_video':
        $file_path = filter_input(INPUT_GET, 'file_path');
        $stream = new VideoStream($file_path);
        $stream->start();
        exit;
}
?>

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM