Java PreparedStatement：com.microsoft.sqlserver.jdbc.SQLServerException，索引超出范围

Question

I'm trying to execute a SQL query using a Java PreparedStatement in Java 7 using the code below:

PreparedStatement functionalCRsStatement = con.prepareStatement(
    "select * from openquery(SERVER,\n" +
    "\t'Select X , Y, Z,  A from  D r\n" +
    "\tINNER JOIN E c\n" +
    "\tON r.RNID = c.RNID\n" +
    "\twhere  c.Y = ?')\n");

functionalCRsStatement.setString(2, x);

I get the following error message: com.microsoft.sqlserver.jdbc.SQLServerException: The index 2 is out of range.

PS: I'm sure of the correctness of the SQL query because I successfully tested it without a PreparedStatement , I just replaced the real name of the columns in the query by fake ones (X, Y, Z) to hide potentially confidential information.

EDIT : I get a similar error when using setString(1, x) => index 1 is out of range

Answer 1

As @JonK commented, you have apostrophes in your query, which means your parameter is actually inside a string where the SQL engine won't bind a value (whether you use 1 or 2 as the index):

PreparedStatement functionalCRsStatement = con.prepareStatement(
    "select * from openquery(APRPRD,\n" +
    "\t'Select X , Y, Z,  A from  D r\n" +
    "\tINNER JOIN E c\n" +
    "\tON r.RNID = c.RNID\n" +
    "\twhere  c.Y = ?')\n");

contains this query (with SQL syntax highlighting, which shows the whole string)

select * from openquery(APRPRD,
        'Select X , Y, Z,  A from  D r
        INNER JOIN E c
        ON r.RNID = c.RNID
        where  c.Y = ?')

A SQL engine never inspects the inside of a string. How would you insert a string containing a question mark otherwise?

Answer 2

It seems you only have one ? in your statement, so you can't make a reference to the second index (2) in the functionalCRsStatement.setString(2, x); , because as it says, it's out of range.

you should use

 functionalCRsStatement.setString(1, x);

Answer 3

您的查询中只有一个绑定变量占位符（ ? ）-因此应将其绑定到索引为1而不是2的索引中：

functionalCRsStatement.setString(1, x); // Was 2 in the OP

Answer 4

You have only one parameter to set in your prepared statement. the set method to set parameter in prepared statement checks index of the ? in the prepared statement and sets the value to prepared statement accordingly.

So in your case there is only 1 ? so in an array of values to be passed for prepared statement is 1. and you are trying to pass the value at the index 2 hence it says The

index 2 is out of range.

Try the same with index 1. as you have only 1 parameter to be set.

eg functionalCRsStatement.setString(1, x);

remember the value x will be stored to the ? at 1st index in the prepared statement.

EDIT : Also remember the type to the value to be passed. if you are setting value of X as int you need to call setInt(1,x). in this case it will not able to find first index os String and throw an error of index out of range.

Answer 5

The prepared statement is not recognizing any param, for is this query contains 0 params because of mal-written string; try this :

PreparedStatement functionalCRsStatement = con.prepareStatement(
    "select * from openquery(APRPRD," +
    "'Select X , Y, Z,  A from  D r" +
    "INNER JOIN E c" +
    "ON r.RNID = c.RNID ')" +
    "where  c.Y = ?");