Python：subprocess.Popen（）。communicate（）将SSH命令的输出打印到标准输出，而不是返回输出

Question

Here's a copy of my python terminal:

>> import subprocess
>> import shlex
>> host = 'myhost'
>> subprocess.Popen(shlex.split('ssh -o LogLevel=error -o StrictHostKeyChecking=no -o PasswordAuthentication=no -o UserKnownHostsFile=/dev/null -o BatchMode=yes %s "hostname --short"' % (host))).communicate()
myhost
(None, None)

I would expect the output to be ('myhost', None) . Why isn't the output being stored in the return tuple for communicate()?

Answer 1

You need to give the subprocess.Popen call a stdout argument. For example:

>>> subprocess.Popen("ls", stdout=subprocess.PIPE).communicate()
(b'Vagrantfile\n', None)
>>>

The output of the command then appears where you expect it.