[英]Get all rows and apply sum on a column
I have a table with four columns and 5 rows, I want all the 5 rows with sum of one column. 我有一个包含四列和五行的表,我希望所有5行都有一列的总和。 Is it possible in MySQL? 在MySQL中有可能吗?
name id rank points
sam 1 4 34
ram 2 6 45
hari 3 1 87
kum 4 7 56
raj 5 5 20
What I need is name id rank points and sum of points where rank above 4. 我需要的是名称id等级点和等于 4以上的点数之和。
Expected result 预期结果
name id rank points sum
ram 2 6 45 121
kum 4 7 56
raj 5 5 20
Hmmm . 嗯。 . 。 . 。
select name, id, rank, points,
(select sum(t2.points) from t t2 where t2.rank > 4) as `sum`
from t
where rank > 4;
This puts the sum
on each row, but that seems like a reasonable approach. 这将sum
放在每一行上,但这似乎是一种合理的方法。
For you and others, the DML & DDL I used is: 对于您和其他人,我使用的DML和DDL是:
CREATE TABLE `users` (
`name` varchar(5),
`id` int,
`rank` int,
`points` int
);
INSERT INTO users (
`name`, `id`, `rank`, `points`
) VALUES (
'sam', 1, 4, 34
), (
'ram', 2, 6, 45
), (
'hari', 3, 1, 87
), (
'kum', 4, 7, 56
), (
'raj', 5, 5, 20
);
For doing it, you need to have a separate query: 为此,您需要一个单独的查询:
SELECT SUM(`points`) FROM `users` WHERE `rank` > 4
And I would suggest you to append this at the end. 我建议你最后附上这个。
SELECT *, (
SELECT SUM(`points`) FROM `users` WHERE `rank` > 4
) AS `sum` FROM `users` WHERE `rank` > 4
The above will give this as output: 以上将作为输出:
+------+----+------+--------+-----+
| name | id | rank | points | sum |
+------+----+------+--------+-----+
| ram | 2 | 6 | 45 | 121 |
| kum | 4 | 7 | 56 | 121 |
| raj | 5 | 5 | 20 | 121 |
+------+----+------+--------+-----+
Fiddle: http://www.sqlfiddle.com/#!9/1dd6260/5 小提琴: http ://www.sqlfiddle.com/#!9 / dd6260 / 5
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