如果标签重复，如何将信息与html标签内的正则表达式匹配？

Question

Like if I have the tags

<td class="cit-borderleft cit-data">437</td>
<td class="cit-borderleft cit-data">394</td>
<td class="cit-borderleft cit-data">12</td>
<td class="cit-borderleft cit-data">**12**</td>

But I need to match number 12 in the last tag. I am using the regex expression "<td class=\\"cit-borderleft cit-data\\">(.*?)</td>" but it will match all four of the tags.

Answer 1

Don't use regex. Use proper XML/HTML parser like jsoup . If you simply want to get text from last element of type td with classes cit-borderleft cit-data you can use

String html = 
        "<table>" +
        "<td class=\"cit-borderleft cit-data\">437</td>\r\n" + 
        "<td class=\"cit-borderleft cit-data\">394</td>\r\n" + 
        "<td class=\"cit-borderleft cit-data\">12</td>\r\n" + 
        "<td class=\"cit-borderleft cit-data\">**12**</td>" +
        "</table>";
Document doc = Jsoup.parse(html);
Element last = doc.select("td.cit-borderleft.cit-data").last();
System.out.println(last.text());

Output: **12**

If you then want to remove these * simply call replace("*","") on that string and you will get new one without asterisks.

Answer 2

Try this:

<td class=\"cit-borderleft cit-data\">\*\*(.*?)\*\*<\/td>

or simple way, this:

\*\*(\d+)\*\*

Answer 3

Based on your attempt

<td class=\"cit-borderleft cit-data\">(.*?)<\/td>(?![\s\S]*<\/td>)

Demo
added this part (?![\\s\\S]*<\\/td>)

(?!             # Negative Look-Ahead
  [\s\S]        # Character in [\s\S] Character Class
  *             # (zero or more)(greedy)
  <             # "<"
  \/            # "/"
  td>           # "td>"
)               # End of Negative Look-Ahead

Answer 4

I don't get why you're using [tag:regex] to parse an HTML tag but here it is

Regex101
(?<=<td class=\\"cit-borderleft cit-data\\">\\*\\*)\\d*(?=\\*\\*<\\/td>)