[英]Search for word in text file in Python
I have this text file: 我有这个文本文件:
MemTotal,5,2016-07-30 12:02:33,781
model name,3,2016-07-30 13:37:59,074
model,3,2016-07-30 15:39:59,075
I need to find the line with the model. 我需要找到与模型一致的线。
My code: 我的代码:
term = "model"
file = open('file.txt')
for line in file:
line.strip().split('/n')
if term in line:
print line
file.close()
This is the output: 这是输出:
model name,3,2016-07-30 13:37:59,074
model,3,2016-07-30 15:39:59,075
I need only this line as output: 我只需要此行作为输出:
model,3,2016-07-30 15:39:59,075
How can I do this? 我怎样才能做到这一点?
Just replace the line: 只需替换行:
if term in line:
with line : 与线:
if line.startswith('model,'):
It depends on what your file contains. 这取决于您的文件包含什么。 Your example is quite light, but I see a few immediate solutions that don't change your code too much : 您的示例很简单,但是我发现一些即时解决方案不会对您的代码造成太大影响:
Replace term = 'model'
by term = 'model,'
and this will only show the line you want. 更换term = 'model'
通过term = 'model,'
这将只显示你想要的行。
Use some additional criteria, like "must not contain 'name'
" : 使用一些其他条件,例如“不得包含'name'
“ :
Like this: 像这样:
term = 'model'
to_avoid = 'name'
with open('file.txt') as f:
for line in file:
line = line.strip().split('/n')
if term in line and to_avoid not in line:
print line
Additional remarks 补充说明
startswith('somechars')
to check for some characters at the beginning of a string 您可以使用startswith('somechars')
来检查字符串开头的某些字符 strip()
and split(\\n)
in your variable, otherwise nothing happens. 您需要在变量中分配strip()
和split(\\n)
的结果,否则什么也不会发生。 with
instead of opening/closing files 最好使用with
关键字而不是打开/关闭文件 You can split the line by ,
and check for the first field: 您可以按来分隔行,
然后检查第一个字段:
term = "model"
file = open('file.txt')
for line in file:
line = line.strip().split(',') # <---
if term == line[0]: # <--- You can also stay with "if term in line:" if you doesn't care which field the "model" is.
print line
file.close()
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