[英]Laravel 5 Routing ALL routes
I am new to laravel, and im trying to get redirect all incoming requests from /example
to exampleController@index
I am using this route 我是laravel的新手,我试图将所有来自/example
传入请求重定向到exampleController exampleController@index
我正在使用这条路由
Route::match(['get', 'post'], '/example/{any}', ['uses' =>'exampleController@index'])->where('any', '.*');
Everything works fine with /example/any/any/any
, but I am getting No input file specified.
使用/example/any/any/any
一切正常,但是我收到了No input file specified.
error when i try /example/any/any/any.php
Please help me to solve this problem. 我尝试/example/any/any/any.php
时出错请帮我解决这个问题。 Thanks. 谢谢。
Route::match
is only used to match multiple HTTP Verbs
to a route. Route::match
仅用于将多个HTTP Verbs
与路由匹配。
As far as I know you can't achieve what you want, and there is no point to do this. 据我所知,你无法达到你想要的效果,没有必要这样做。
What you may need is Route::resource
check the docs 您可能需要的是Route::resource
检查文档
Managed to get it working by editing NGINX config file. 通过编辑NGINX配置文件来管理它。 In my situation im using laravel 5 homestead with default configuration. 在我的情况下我使用laravel 5宅基地默认配置。 Config file is located /etc/nginx/sites-enabled/homestead.app
. 配置文件位于/etc/nginx/sites-enabled/homestead.app
。 Add try_files $uri $uri/ /index.php?$args;
添加try_files $uri $uri/ /index.php?$args;
right after location ~ \\.php$
. 在location ~ \\.php$
之后location ~ \\.php$
。 Should look similar to this 应该看起来与此类似
location ~ \.php$ {
try_files $uri $uri/ /index.php?$args;
fastcgi_split_path_info ^(.+\.php)(/.+)$;
fastcgi_pass unix:/var/run/php/php7.0-fpm.sock;
....
}
I am not sure as to why, but you can use Route::group with a prefix as such 我不确定为什么,但你可以使用带有前缀的Route :: group
Route::group(['prefix' => 'example'], function() {
Route::get('action/{id}', 'ExampleController@getAction');
});
Going to http://yoursite.com/example/action/111 will use the getAction method in the ExampleController. 转到http://yoursite.com/example/action/111将使用ExampleController中的getAction方法。
public function getAction($id) {
// do something with Example with this $id
}
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