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如何在VSIX项目中的解决方案文件夹中获取项目

[英]How to get project inside of Solution Folder in VSIX project

Hi I am having a problem, with a custom build task inside of a Visual Studio Extension. 您好我有一个问题,在Visual Studio扩展中有自定义生成任务。 I need to identify projects of my custom project type. 我需要识别我的自定义项目类型的项目。 I can do this fine if they are on the root of the solution, but the problem occurs when it is inside of a solution folder. 如果它们位于解决方案的根目录下,我可以做到这一点,但是当它在解决方案文件夹中时会出现问题。 I can get the solution folder as a EnvDTE.Project, but am not sure how to get projects from within that folder. 我可以将解决方案文件夹作为EnvDTE.Project获取,但我不确定如何从该文件夹中获取项目。

I thought I would be able to get it from the projects Collection property but that is null. 我以为我可以从项目Collection属性中获取它,但这是null。

Any assistance would be greatly appreciated. 任何帮助将不胜感激。

if (Scope == EnvDTE.vsBuildScope.vsBuildScopeSolution)
{
    DTE2 dte2 = Package.GetGlobalService(typeof(EnvDTE.DTE)) as DTE2;
    var sol = dte2.Solution;
    EnvDTE.DTE t = dte2.DTE;
    var x = t.Solution.Projects;
    foreach(var proj in x)
    {
       try
       {
           var project = proj as EnvDTE.Project;
           var guid = GetProjectTypeGuids(project);
           if (guid.Contains("FOLDERGUID"))
           {
               //here is where I would get the project from the folder
           }

I managed to resolve this with a bit more research and some trial and error. 我设法通过更多的研究和一些反复试验来解决这个问题。 In case anybody else comes up with this problem, I changed the main code to 如果有其他人提出这个问题,我将主要代码更改为

if (Scope == EnvDTE.vsBuildScope.vsBuildScopeSolution)
{
    errorListProvider.Tasks.Clear();
    DTE2 dte2 = Package.GetGlobalService(typeof(DTE)) as DTE2;
    var sol = dte2.Solution;
    var projs = sol.Projects;
    foreach(var proj in sol)
    {
         var project = proj as Project;
         if (project.Kind == ProjectKinds.vsProjectKindSolutionFolder)
         {
             var innerProjects = GetSolutionFolderProjects(project);
             foreach(var innerProject in innerProjects)
             {
                 //carry out actions here.
             }
         }
    }
}

The code for the GetSolutionFolderForProjects was GetSolutionFolderForProjects的代码是

private IEnumerable<Project> GetSolutionFolderProjects(Project project)
{
    List<Project> projects = new List<Project>();
    var y = (project.ProjectItems as ProjectItems).Count;
    for(var i = 1; i <= y; i++)
    {
        var x = project.ProjectItems.Item(i).SubProject;
        var subProject = x as Project;
        if (subProject != null)
        {
          //Carried out work and added projects as appropriate
        }
    }

    return projects;
}

Hope this helps somebody else. 希望这有助于其他人。

I had a similar question within a T4 template, where I had to find a project by name within the solution, at any level: root, folder, nested folder. 我在T4模板中有一个类似的问题,我必须在解决方案中找到任何级别的项目:根,文件夹,嵌套文件夹。

For reference purposes, I'm pasting it here. 出于参考目的,我在这里粘贴它。 It's totally based on the solution from @DaveGreen, so credits to him: 它完全基于@DaveGreen的解决方案,因此归功于他:

<#@ import namespace="System.Linq" #>
<#
var dte = (DTE)hostServiceProvider.GetService(typeof(DTE));

var project = GetProject(dte.Solution, "ProjectName");
#>
<#+
public static Project GetProject(Solution solution, string name)
{
    var project = GetProject(solution.Projects.OfType<Project>(), name);

    if (project == null)
    {
        throw new Exception($"Project {name} not found in solution");
    }

    return project;
}

public static Project GetProject(IEnumerable<Project> projects, string name)
{
    foreach (Project project in projects)
    {
        var projectName = project.Name;
        if (projectName == name)
        {
            return project;
        }
        else if (project.Kind == EnvDTE80.ProjectKinds.vsProjectKindSolutionFolder)
        {
            var subProjects = project
                .ProjectItems
                .OfType<ProjectItem>()
                .Where(item => item.SubProject != null)
                .Select(item => item.SubProject);

            var projectInFolder = GetProject(subProjects, name);

            if (projectInFolder != null)
            {
                return projectInFolder;
            }
        }
    }

    return null;
}
#>

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