在if语句中使用爆破时in_array失败

Question

This attamept is to create a search condition where eventually the output will be processed to show results based on increasing order of matches

"PHP implode function in if and foreach condition [closed]" is a different question !

Why is the following code failing ?

$terms = array("HELLO", "HI", "HOWDY");
$row = array("HELLO", "HI", "Hey");
$chkcond = "in_array('".implode("',$"."row".")"." && in_array"."('",$terms)."',$"."row)";

echo "$chkcond<br/><br/>";

if ($chkcond) {
    echo "All Found in Array !<br>";}else{echo "Not Found !<br/>";
}

The echo result is

in_array('HELLO',$row) && in_array('HI',$row) && in_array('HOWDY',$row)

And the if condition outputs "All Found in Array !"

When the if condition says that all three terms have to be in the row array to be " All Found in Array ", then why is it returning True when " Howdy " doesn't exist in the row array ?

Answer 1

juste use array_diff http://php.net/array_diff

<?php
$terms=array("HELLO","HI","HOWDY");
$row=array("HELLO","HI","Hey");

$diff = array_diff($terms, $row);

if (0 === count($diff)){echo "All terms Found in Array row !<br>";}else{echo "Not all terms Found in Array row !<br>";}


$terms=array("HELLO","HI","HOWDY");
$row=array("HELLO","HI","Hey","HOWDY");

$diff = array_diff($terms, $row);

if (0 === count($diff)){echo "All terms Found in Array row !<br>";}else{echo "Not all terms Found in Array row !<br>";}

Answer 2

You could use array_diff

Something like:

<?php
$terms=array("HELLO","HI","HOWDY");
$row=array("HELLO","HI","Hey");
$chkcond=array_diff($terms, $row);

var_dump($chkcond);

if(empty($chkcond)) {
    echo "All Found in Array !<br>";
} else {
    echo "Not Found !<br>";
}
?>

Answer 3

Not sure what you are attempting but you can use array_diff.

$terms = array("HELLO","HI","HOWDY");
$row   = array("HELLO","HI","Hey");

$differences = array_diff($terms, $row);

if ($differences) {
  echo "All Found in array";
} else {
  "Not Found !<br>";
}

https://secure.php.net/manual/en/function.array-diff.php

Answer 4

If you would like to stick with in_array you need to loop your terms:

<?php
    $terms=array("HELLO","HI","HOWDY");
    $row=array("HELLO","HI","Hey");

    $chkcond = true;
    foreach($row as $needle){
        if(!in_array($needle, $terms)){
            $chkcond = false;
            break;         
        }
    }

    if($chkcond){
        echo "All Found in Array !<br>";
    } else {
        echo "Not Found !<br>";
    }
?>

Heck re-reading the manual http://php.net/manual/en/function.in-array.php you do not even need to loop:

<?php
    $terms=array("HELLO","HI","HOWDY");
    $row=array("HELLO","HI","Hey");
    if(in_array($row, $terms)){
        echo "All Found in Array !<br>";
    } else {
        echo "Not Found !<br>";
    }

?>