ule esb中的时间戳转换

Question

I need to capture file last modified date in yyyy-MM-dd format .

I tried #[message.inboundProperties.timestamp] but getting timestamp like 142565954 .

Yes, I know it can be done using goovy or java.

Please can anybody suggest to convert the timestamp 142565954 to yyyy-MM-dd format with mule expression language?

Answer 1

Please reference the below link: https://docs.mulesoft.com/mule-user-guide/v/3.6/mule-expression-language-date-and-time-functions

Try something like this :

#[new org.mule.el.datetime.DateTime(new Date(message.inboundProperties.timestamp),"E MMM dd HH:mm:ss z yyyy")] 

Answer 2

试试这个，它与我server.dateTime

#[message.inboundProperties.timestamp.format('yyyy-MM-dd')]

Answer 3

该时间戳（message.inboundProperties.timestamp）是消息时间戳，而不是文件时间戳。

Answer 4

如果您在dataweave中使用，则请写成message.inboundProperties.timestamp：：date {format：“ yyyy-MM-dd”}