如何在Python中为每分钟创建UNIX时间戳

Question

I want to create a UNIX timestamp for the date 2014-10-31 for every minute of the day. I have got a timestamp for the date but not for every minute -

import datetime
date = '2014-10-31'
t_stamp = int(time.mktime(datetime.datetime.strptime(date, "%Y-%m-%d").timetuple()))
print t_stamp

I want to save all these entries in a file which I need to access later to get specific entries only.

If I need to access one of the timestamp records using a date and specific time, how can it be done? For example, I need to find the entries for 2014-31-10 for the time between 20:00 and 20:05 , how can it be done?

Any help would be appreciated!

Updated:

import datetime
import ipaddress
from random import randint

for x in ip_range.hosts():

    for h in range(24): #24 hours
        for i in range(60): # 60 minutes
            f.write(str(t_stamp)+'\t'+str(x)+'\t0\t'+str(randint(0,100))+'%\n')
            f.write(str(t_stamp)+'\t'+str(x)+'\t1\t'+str(randint(0,100))+'%\n')

            t_stamp += 60 # one minute

Now I am looking to create a log file for every minute. How can that be done?

Answer 1

t_stamp = int(time.mktime(datetime.datetime.strptime(date, "%Y-%m-%d").timetuple()))
for h in range(24): 24 hours
    for i in range(60): # 60 minutes
        print t_stamp
        t_stamp += 60 # one minute

Answer 2

Hope this helps.

Storing timestamps in a database is simply redundant unless the required values cannot be corelated ie billing transactions' time. Here, your required range values have a start and end time, and you know them. You also know the interval between each value is 1 minute.

import datetime

tvalue = datetime.datetime(2014,10,31,0,0).timestamp()  #yy mm dd 0 0

startval = ((REQD_HOUR)*3600 + (REQD_MIN)*60) #required start time

endval = ((REQD_HOUR_E)*3600 + (REQD_MIN_E)*60) # range end time

while (endval > startval):
 print(tvalue+startval)
 startval+=60