[英]adding where clauses to a many many relationship
I want to build a directory for restaurant, the search is based in three condition the problem that I have is add the third where clause that uses typecuisine
like you see in code the 2 first conditions are good my entity 我想为餐厅建立目录,搜索是基于三个条件的,我
typecuisine
的问题是添加使用typecuisine
的第三个where子句,就像在代码中看到的那样,第2个条件是我的实体
var query = db.Restaurants.AsQueryable();
if (!string.IsNullOrEmpty(Name))
query = query.Where(c => c.Nom.Contains(Name));
if (RegionId != Guid.Empty)
query = query.Where(c => c.RegionId == RegionId);
//how to get typecuisine ID from table Restaurant instead it's only in table TypeCuisine
if (typeId != Guid.Empty)
query = query.Where(tc=> tc.TypeCuisines.Where(r=>r.TypeCuisineId == typeId));
return query.ToList();
The .Where
is expecting a return type of bool
and you are returning the results of an inner Where
, meaning an IEnumerable
. .Where
期望返回bool
类型,而您返回的是内部Where
的结果,即IEnumerable
。
What you are missing is the .Any()
function instead of the inner Where
. 您缺少的是
.Any()
函数,而不是内部Where
。
var query = db.Restaurants.AsQueryable();
if (!string.IsNullOrEmpty(Name))
query = query.Where(c => c.Nom.Contains(Name));
if (RegionId != Guid.Empty)
query = query.Where(c => c.RegionId == RegionId);
if (typeId != Guid.Empty)
query = query.Where(tc=> tc.TypeCuisines.Any(r => r.TypeCuisineId == typeId));
return query.ToList();
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