尝试合并jquery.each函数的所有值

Question

Look at my code, I am trying to combine all value from the jquery.each to a string like this ok,good, and then passed to ajax value. Appreciate. or array('ok','good') acceptable also

 var global = { "44":["onset","frequency"], "45":["onset"] }; var $val = global[44]; jQuery.each( $val, function( key ,value) { var value = $('#'+value).val(); }); var $combine = ;//not sure how to combine all value like this (ok,good), or array(ok,good) acceptable also var data= { action: 'check_first', AjaxFrontNonce : ajax_csky.AjaxFrontNonce, combine : $combine } 

 <input type="hidden" id="onset" value="ok"> <input type="hidden" id="frequency" value="good"> 

Answer 1

Try this:

 var global = { "44":["onset","frequency"], "45":["onset"] }; var $val = global[44]; var values = []; jQuery.each( $val, function( key ,value) { values.push($('#'+value).val()); }); var $combine = '(' + values.join(',') + ')'; console.log($combine); 

 <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <input type="hidden" id="onset" value="ok"> <input type="hidden" id="frequency" value="good"> 

Answer 2

You can use $.map to go over all of the items and return the value for each element.
There is an example of both Array and String values, you can use whichever works better for you.

 var global = { "44":["onset","frequency"], "45":["onset"] }; var $val = global[44]; combinedAr = $.map($val, function(val) { return $('#'+val).val(); }); combinedStr = combinedAr.join(","); var data= { action: 'check_first', AjaxFrontNonce : ajax_csky.AjaxFrontNonce, combine : combinedStr } 

 <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <input type="hidden" id="onset" value="ok"> <input type="hidden" id="frequency" value="good"> 

Answer 3

Try this working snippet

 var global = { "44": ["onset", "frequency"], "45": ["onset"] }; var $val = global[44]; var arr = []; $.each($val, function(key, val) { var value = $('#' + val).val(); arr.push(value); }); var $combine = arr; //not sure how to combine all value like this (ok,good), or array(ok,good) acceptable also console.log($combine); var data = { action: 'check_first', //AjaxFrontNonce : ajax_csky.AjaxFrontNonce, not defiend combine: $combine } 

 <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <input type="hidden" id="onset" value="ok"> <input type="hidden" id="frequency" value="good">