如何将引用类型传递给Url.Action

Question

I'm trying to pass my model into Url.Action :

@Model FilterVm
@Url.Action("Index", "Home", new { filter = @Model })

but when my method is called, I got always null in parameter

public ActionResult Index (FilterVm filter)

How can I pass my model as a parameter in Url.Action?

Answer 1

You need to pass all fields of your model separately. For example, if your model contain 2 fields Name and Id Url.Action must be

@Url.Action("Index", "Home", new { Name=Model.Name, Id=Model.Id })

Also Model declaration in your view need to be in lower case

@model FilterVm