[英]How can i map a child object with AutoMapper?
I am not sure if i am over thinking this or not, but i cannot sus this out. 我不确定我是否在考虑这个问题,但是我不能对此提出质疑。
I have a parent object here called Template 我在这里有一个称为模板的父对象
public Template()
{
public long Id { get; set; }
public Scoring SubProperty { get; set; }
}
Here is my Scoring object which is a child property of Template 这是我的计分对象,它是Template的子属性
public enum MyEnum : short
{
Basic = 0
}
public Scoring()
{
public MyEnum Type { get; set; }
public string Text { get; set; }
}
I have a TemplateModel defined, like so, which i want to convert to 我有一个这样定义的TemplateModel,我想将其转换为
public TemplateModel()
{
public long Id { get; set; }
public string Type { get; set; }
public string Text { get; set; }
}
In my AutoMapper Profile, i have set this up like so, to covert Template to TemplateModel. 在我的AutoMapper配置文件中,我已经将其设置为将Template隐藏为TemplateModel。
public class TemplateProfile : Profile
{
protected override void Configure()
{
// converters
this.CreateMap<TemplateType, string>().ConvertUsing(new TemplateTypeConverter());
// models
this.CreateMap<Template, TemplateModel>()
.ForMember(dest => dest.Type, opt => opt.MapFrom(src => src.Scoring.Type))
.ForMember(dest => dest.Text, opt => opt.MapFrom(src => src.Scoring.Text));
}
/// <summary>
/// Convert TemplateType to string
/// </summary>
private class TemplateTypeConverter : ITypeConverter<TemplateType, string>
{
public string Convert(ResolutionContext context)
{
return context.SourceValue.ToString().ToLower();
}
}
}
How can i convert TemplateModel back into Template? 如何将TemplateModel转换回Template?
If i add the following, i get an exception, because dest.Scoring.Type is not a root property. 如果添加以下内容,则会出现异常,因为dest.Scoring.Type不是根属性。
this.CreateMap<TemplateModel, Template>()
.ForMember(dest => dest.Scoring.Type, opt => opt.MapFrom(src => src.Type))
.ForMember(dest => dest.Scoring.Text, opt => opt.MapFrom(src => src.Text));
Any help much appreciated. 任何帮助,不胜感激。 In this case a
Template
must always have a Scoring
object, but in other cases i have optional properties. 在这种情况下,
Template
必须始终具有Scoring
对象,但在其他情况下,我具有可选属性。 If someone could help me with both that would be great. 如果有人可以帮助我,那就太好了。
this.CreateMap<TemplateModel, Template>()
.ForMember(dest => dest.SubProperty, opt => opt.MapFrom(src => src));
this.CreateMap<TemplateModel, Scoring>()
.ForMember(dest => dest.Type, opt => opt.MapFrom(src => src.Type))
.ForMember(dest => dest.Text, opt => opt.MapFrom(src => src.Text));
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