[英]Decode a base64 string to a decimal string
I have a string say FhY=
which has been encoded to hex. 我有一个字符串说
FhY=
已被编码为十六进制。 So when run 所以跑步的时候
>>> b6 = 'FhY='
>>> b6.decode('base64')
'\x16\x16'
This is a hex string that once converted should be 22 22
. 这是一个十六进制字符串,一旦转换应该是
22 22
。 This result has been proven on the site https://conv.darkbyte.ru/ . 该结果已在网站https://conv.darkbyte.ru/上得到证实。 However, I cannot seem to do a proper conversion from base64 to decimal representation.
但是,我似乎无法从base64到十进制表示进行适当的转换。 Some of the challenges I am facing are
我面临的一些挑战是
base64 > base16
( Convert a base64 encoded string to binary ), base64 > binary > decimal
( Convert hex string to int in Python ) both of which have failed. base64 > base16
( 将base64编码的字符串转换为二进制 ), base64 > binary > decimal
( 在Python中将十六进制字符串转换为int )两者都失败了。 Please assist. 请协助。
You need to convert each byte from the decoded string to its decimal value. 您需要将解码后的字符串中的每个字节转换为十进制值。 So this should solve it:
所以这应该解决它:
b6 = 'FhY='
' '.join([ str(ord(c)) for c in b6.decode('base64') ])
Results in 22 22
结果
22 22
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