从enum到enum的分配不兼容*

Question

My code got an error below: incompatible types when assigning to type enum cell from type enum cell *

I have tried many ways to fix it but didnt work. This is my code:

BOOLEAN init_first_player(struct player * first, enum cell * token) {
    strcpy(first->name, "Bob");
    first->score = 0;

    int colorNo = rand() % 2;
    token = (colorNo + 1 == 1) ? RED : BLUE;

    first->token = token; //Error occurs here
    return TRUE;
}

this is my data structure:

struct Player {
    char name[20];
    enum cell token; //takes 0 - 1 - 2
    unsigned score;
};

enum cell {
    BLANK, RED, BLUE
};

Someone can please fix the code as I don't know what I have been doing wrong.

Answer 1

You are passing token in as a pointer, presumably because you want to see the modified value at the call site . (If you don't care about the modified value, you shouldn't send it in this function at all).

So, you need to dereference it when assigning:

// use *token (instead of just token) to dereference and assign
*token = (colorNo + 1 == 1) ? RED : BLUE;

Same when assigning it to first->token :

first->token = *token;

Answer 2

In init_first_player token is a pointer to enum

In your structure first , token is an enum.

You cannot assign a pointer to enum to an enum.

You should use

*token = (colorNo + 1 == 1) ? RED : BLUE;
first->token = *token