[英]Python GetHostId.py getting sys.argv[1] IndexError: list index out of range
i am working on a python script to be a multi tool for getting DNS information on servers in a enterprise env. 我正在使用python脚本作为要在企业环境中的服务器上获取DNS信息的多功能工具。 so far the script i have is using python 3.5.
到目前为止,我拥有的脚本正在使用python 3.5。 i am using argparse for creating command line options, which i am trying to create an if/ elif / else statement which contains the different selections.
我正在使用argparse创建命令行选项,我正在尝试创建一个包含不同选择的if / elif / else语句。 the main error message i am getting is:
我收到的主要错误消息是:
./GetHostName.py
Traceback (most recent call last):
File "./GetHostName.py", line 34, in <module>
remoteServer = sys.argv[1]
IndexError: list index out of range
that is when the command is run by itself. 也就是命令本身运行时。 when it is run with a host name at the end ./GetHostName.py hostName it gives this message:
当它以./GetHostName.py hostName结尾的主机名运行时,它将显示以下消息:
GetHostName.py: error: unrecognized arguments: hostName
I didn't put real name of server for security issues.... When i use the argparse options say like the -f option for getting the FQDN, it gives this response... 对于安全性问题,我没有提供服务器的真实名称。...当我使用argparse选项时,如-f选项那样获取FQDN,它会给出此响应...
./GetHostName.py -f hostName
3
-f
from the way it appears, it is taking the -f as input for the server name, when it should only be the input for argparse input. 从出现的方式来看,它仅将-f作为服务器名称的输入,而应仅将其作为argparse输入的输入。 i have tried everything to fix it that i can think of.
我已经尽力解决了我能想到的问题。 i have encased the main code body in a main function, that didn't work so i removed it.
我已经将主要代码主体包裹在一个主要函数中,但是没有用,所以我删除了它。 i use the try: statement and exception statements.
我使用try:语句和异常语句。 that didn't work.
那没有用。 i am wondering if there is something just basically wrong with my programming logic at this point...
我想知道此时我的编程逻辑是否存在根本上的错误...
this here is the code from the script: 这是脚本中的代码:
#!C:\Bin\Python35\python.exe
#
# import libraries
import sys, os
import argparse as ap
import socket
# Command Line interface setup
def argParse():
#Command Line arg parse
parser=ap.ArgumentParser(description='A tool to get a remote servers DNS information.')
parser.add_argument("-a", "--address", default="fqdn", help="Gets IP address from host name.")
parser.add_argument("-f", "--fqdn", default="fqdn", help="Gets the FQDN address of server.")
parser.add_argument("-d", "--addrinfo", default="fqdn", help="Gets the FQDN address of server.")
parser.add_argument("-l", "--local", default="fqdn", help="Gets info on local host.")
parser.add_argument("-Pr", "--proto", default="fqdn", help="Translate an Internet protocol name to a constant suitable for passing as the (optional) third argument to the socket() function.")
parser.add_argument("-n", "--nameinfo", default="fqdn", help="Gets name and port on remote host.")
parser.add_argument("-Sn", "--servbyname", default="fqdn", help="Translate an Internet service name and protocol name to a port number for that service.")
parser.add_argument("-Sp", "--servbyport", default="fqdn", help="Translate an Internet port number and protocol name to a service name for that service.")
parser.add_argument("-t", "--timeout", default="fqdn", help="Return the default timeout in seconds for new socket objects.")
parser.add_argument("-v", "--verbose", default="fqdn", help="Increase output verbosity")
return parser.parse_args()
#remoteServer = input().strip().split()
args=argParse()
if args.fqdn:
remoteServer = sys.argv[1]
print (len(sys.argv))
remoteServerIP = socket.getfqdn(remoteServer)
print (remoteServerIP)
elif args.address:
remoteServer = sys.argv[2]
print (len(sys.argv))
remoteServerIP = socket.gethostbyname(remoteServer)
print (remoteServerIP)
elif args.addrinfo:
remoteServer = sys.argv[3]
print (len(sys.argv))
remoteServerIP = socket.getaddrinfo(remoteServer)
print (remoteServerIP)
elif args.local:
remoteServer = sys.argv[4]
print (len(sys.argv))
remoteServerIP = socket.gethostname()
print (remoteServerIP)
elif args.proto:
remoteServer = sys.argv[5]
print (len(sys.argv))
remoteServerIP = socket.getprotobyname(remoteServer)
print (remoteServerIP)
elif args.servbyname:
remoteServer = sys.argv[6]
print (len(sys.argv))
remoteServerIP = socket.getservbyname(remoteServer)
print (remoteServerIP)
elif args.servbyport:
remoteServer = sys.argv[7]
print (len(sys.argv))
remoteServerIP = socket.getservbyport(remoteServer)
print (remoteServerIP)
elif args.timeout:
remoteServer = sys.argv[8]
print (len(sys.argv))
remoteServerIP = socket.getdefaulttimeout(remoteServer)
print (remoteServerIP)
elif args.verbose:
remoteServer = sys.argv[9]
print (len(sys.argv))
remoteServerIP = socket.gethostbyaddr(remoteServer)
print (remoteServerIP)
else:
args.nameinfo
remoteServer = sys.argv[10]
print (len(sys.argv))
remoteServerIP = socket.getnameinfo(remoteServer)
print (remoteServerIP)
any help would be appreciated. 任何帮助,将不胜感激。 please note that when i run a script with just this in it, it works just fine:
请注意,当我运行一个仅包含脚本的脚本时,它就可以正常工作:
#!C:\Bin\Python35\python.exe
#
import sys, os
import argparse
import socket
# Command Line interface setup
def main():
remoteServer = sys.argv[1]
remoteServerIP = socket.gethostbyaddr(remoteServer)
print (remoteServerIP)
if __name__ == '__main__':
main()
thanks in advance. 提前致谢。 -Betzelel
-Betzelel
PS the code may look out of format, due to having to copy and paste into this blog, and manually putting 4 spaces on to each line to get it to show up as code lol. PS:由于必须复制并粘贴到此博客中,并且手动在每行上放置4个空格以使其显示为代码大声笑,因此代码的格式可能不正确。
I've had this problem long time ago. 我很久以前就有这个问题。 To fix this I've changed
为了解决这个问题,我改变了
parser.add_argument("-a", "--address", default="fqdn", help="Gets IP address from host name.")
in 在
parser.add_argument("-a", "--address", default="fqdn", help="Gets IP address from host name.", dest=ipfromhostname)
So for getting the value from -a
you have to change 因此,要从
-a
获取值,您必须进行更改
remoteServer = sys.argv[1]
in 在
remoteServer = args.ipfromhostname
where ipfromhostname
is the dest
value. 其中
ipfromhostname
是dest
值。
EDIT: 编辑:
You have to do this operation for every parser.add_argument
您必须对每个
parser.add_argument
执行此操作parser.add_argument
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