从xml文件获取属性php

Question

<?xml version="1.0" encoding="UTF-8"?>
  <abc-response>
   <error-messages>
    <errors code="302">
         User does not have access to this Product 
    </errors>
  </error-messages>
</abc-response>

am using simplexml_load_string and using the attribute function to get the code and I keep getting a null value.

 $results = simplexml_load_string($response);

 $errorCode = $results->attributes()->{'errors'};

Answer 1

You need to navigate to the element with the attribute you want. There are lots of ways.

echo $results->{'error-messages'}->errors['code'];//302

This works just fine since there's just one error-messages and one errors . If you had several, you could use array notation to indicate the one you want. So the line below also echoes 302

echo $results->{'error-messages'}[0]->errors[0]['code'];

You could even use xpath , a query language to traverse xml. The // will return all nodes by name:

echo $results->xpath('//errors')[0]->attributes()->code; //302

echo shows a number, but it's still an object. If you'd like to capture just the integer, cast it like this:

$errorCode = (int) $results->{'error-messages'}->errors['code'];

Check out this really helpful intro .