StringBuilder构造函数接受StringBuilder对象 - 为什么？

Question

The class StringBuilder defines four constructors, and none of them accepts a StringBuilder , yet the following compiles:

StringBuilder sb = new StringBuilder(new StringBuilder("Hello"));

Does this mean that the anonymous StringBuilder object gets somehow converted to a String internally by the compiler?

Answer 1

A StringBuilder is a CharSequence (it implements that interface), and there is a constructor taking a CharSequence . This is why the given code compiles:

StringBuilder sb = new StringBuilder(new StringBuilder("Hello"));

What this constructor does is simply initialize the new StringBuilder with the content of the given CharSequence . The result will be the same as having

StringBuilder sb = new StringBuilder("Hello");

Answer 2

There is a constructor that takes in a CharSequence which is an interface that is implemented by StringBuilder and by String (among other classes).

http://docs.oracle.com/javase/8/docs/api/java/lang/CharSequence.html