以bash列出大于100K的文件

Question

I want to list the files recursively in the HOME directory. I'm trying to write my own script , so I should not use the command find or ls . My script is:

#!/bin/bash

minSize=102400;

printFiles() {
    for x in "$1/"*; do
        if [ -d "$x" ]; then
            printFiles "$x";
        else
            size=$(wc -c "$x");
            if [[ "$size" -gt "$minSize" ]]; then
                echo "$size";
            fi
        fi
    done
}

printFiles "/~";

So, the problem here is that when I run this script, the terminal throws Line 11: division by 0 and /home/gandalf/Videos/*: No such file or directory . I have not divided by any number, why I'm getting this error?. And the second one?

Alternatively, I can't use find or ls because I have to display the files one by one asking to the user if he want to see the next file or not. This is possible using the command find or ls or only can be done writing my own function?

Thanks.

Answer 1

size=$(wc -c "$x");

That's the line that is failing. When you run that wc command manually you should be able to see why:

$ wc -c /tmp/out
5 /tmp/out

The output contains not only the file size but also the file name. So you can't use $size with the -gt comparator on the next line. One way to fix that is to change the wc line to use cut (or awk , or sed , etc) to keep just the file size.

size=$(wc -c "$x" | cut -f1 -d " ")

A simpler alternative suggested by @mklement0:

size=$(wc -c < "$x")