request.get返回 <!doctype> 代替 <Response>

Question

I have an issue with requests.get(). 我对request.get（）有问题。 If I paste the URL manually into the code as here: 如果我将网址手动粘贴到代码中，如下所示：

r = requests.get('https://berlin.kauperts.de/Strassen/Igelsteig-12557-Berlin.html')
print(r)

I get: <Response [200]> . 我得到： <Response [200]> 。 Which works quite fine. 哪个效果很好。 Instead if I try to ask for the requests out of a list of files as in: 相反，如果我尝试从文件列表中请求请求，如下所示：

indir = '/home/d/Desktop/civiv_hacking/Streetnames/dump/berlin.kauperts.de/Strassen'
for root, dirs, filenames in os.walk(indir):
  for z in filenames:
     x = urlparse.urljoin('https://berlin.kauperts.de/Strassen/', z+'/'),
     [t[0] for t in x],
     print(t),
     for r in requests.get(t):              
        print(r),

I get: https://berlin.kauperts.de/Strassen/Igelsteig-12557-Berlin/ <!DOCTYPE html> <html lang="de" xml:lang="de" xmlns="http://www.w3.org/1999/xhtml"> How can I make requests.get() return <Response [200]> instead of just the doctype information? 我得到： https://berlin.kauperts.de/Strassen/Igelsteig-12557-Berlin/ <!DOCTYPE html> <html lang="de" xml:lang="de" xmlns="http://www.w3.org/1999/xhtml"> : https://berlin.kauperts.de/Strassen/Igelsteig-12557-Berlin/ <!DOCTYPE html> <html lang="de" xml:lang="de" xmlns="http://www.w3.org/1999/xhtml">如何使request.get（）返回<Response [200]>而不是仅仅返回文档类型信息？

Answer 1

If you want to see the Response string representation , you should not be iterating over it, just print: 如果要查看Response 字符串表示形式 ，则不应该对其进行迭代，只需打印：

url = urlparse.urljoin('https://berlin.kauperts.de/Strassen/', z)
response = requests.get(url)
print(response)  # would print "<Response [200]>"

request.get返回 <!doctype> 代替 <Response>

问题描述

1 个解决方案

解决方案1
1 2016-08-15 15:57:38

request.get返回 <!doctype> 代替 <Response>

问题描述

1 个解决方案

解决方案1 1 2016-08-15 15:57:38

解决方案1
1 2016-08-15 15:57:38