如何使用Javascript或Lodash从arrayList中删除特定对象

Question

I have two objects like this.

var find = [{
    licenseId: 'A123',
    batchId: '123',
    name: 'xxx'
},
    {
        licenseId: 'B123',
        batchId: '124',
        name: 'yyy'
    }];


var result = [
    {
        licenseId: 'A123',
        batchId: '123',
        name: 'xxx',
        tag: 'college',
        sem: 'fourth'
    },

    {
        licenseId: 'B123',
        batchId: '124',
        name: 'yyy',
        tag: 'college',
        sem: 'third'
    },
    {
        licenseId: '1111',
        batchId: 'C123',
        name: 'yyy',
        tag: 'college',
        sem: 'second'
    },


    {
        licenseId: '3456',
        batchId: 'B123',
        name: 'yyy',
        tag: 'college',
        sem: 'second'
    }];

I want to remove the objects of Result which has matched with all three properties of find object. I want the result should be like this:

[{
        licenseId: '1111',
        batchId: 'C123',
        name: 'yyy',
        tag: 'college',
        sem: 'second'
    },


    {
        licenseId: '3456',
        batchId: 'B123',
        name: 'yyy',
        tag: 'college',
        sem: 'second'
    }];

Can you assist?

Answer 1

Following code should work.

for(var j=0;j < find.length;j++){
  for (var i = 0; i < result.length; i++) {
    if ((result[i].licenseId == find[j].licenseId)  && 
        (result[i].name == find[j].name) && 
        (result[j].batchId == find[j].batchId)) {
      result.splice(i, 1);
      break;
    }
  }
}

Answer 2

You can use array find method to find if the result array has the matched element. Here licenseId is used to find if result array contain the same element.

If it is found there use index argument to find it's index. Then use splice to delete the specific element.

also you can use array forEach to loop through the find array

var find = [// json objects];

var result = [// json objects];
find.forEach(function(item){

var _findInResult = result.find(function(itemInResult,index){
   if(itemInResult.licenseId == item.licenseId){
   result.splice(index,1);
   }
   return itemInResult.licenseId == item.licenseId
})

})
console.log(result)

JSFIDDLE

Answer 3

I would use remove and some

_.remove(result, function(obj) {
    return _.some(find, {
        licenseId: obj.licenseId,
        batchId: obj.batchId,
        name: obj.name,
    });
});

 var find = [{ licenseId: 'A123', batchId: '123', name: 'xxx' }, { licenseId: 'B123', batchId: '124', name: 'yyy' }]; var result = [ { licenseId: 'A123', batchId: '123', name: 'xxx', tag: 'college', sem: 'fourth' }, { licenseId: 'B123', batchId: '124', name: 'yyy', tag: 'college', sem: 'third' }, { licenseId: '1111', batchId: 'C123', name: 'yyy', tag: 'college', sem: 'second' }, { licenseId: '3456', batchId: 'B123', name: 'yyy', tag: 'college', sem: 'second' }]; _.remove(result, function(obj) { return _.some(find, { licenseId: obj.licenseId, batchId: obj.batchId, name: obj.name, }); }); console.log(result); 

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