如何基于布尔属性和名称属性对数组进行排序？

Question

I have an array of objects that look like this:

[
  {
    name: s1,
    isDefault: false
  },
  {
    name: s2,
    isDefault: true
  },
  {
    name: s3,
    isDefault: false
  }
]

I want to sort this array so that the element with isDefault: true is placed first, and have the rest follow this object in alphabetical order.

In other words:

[
  {
    name: s2,
    isDefault: true
  },
  {
    name: s1,
    isDefault: false
  },
  {
    name: s3,
    isDefault: false
  }
]

I know how to accomplish the first condition:

objPanoramas.sort((a, b) => {
  return a.isDefault < b.isDefault
})

How can I integrate the second condition?

Answer 1

objPanoramas.sort((a, b) => {
  if (a.isDefault == b.isDefault) {
    name1 = a.name;
    name2 = b.name;
    return name1<name2?-1:(name1>name2?1:0)
  }
  return a.isDefault < b.isDefault
})

Answer 2

try this

 objPanoramas = [{ name: "s1", isDefault: false },{ name: "s1", isDefault: true }, { name: "s2", isDefault: true }, { name: "s3", isDefault: false }] objPanoramas.sort((a, b) => { if ((a.isDefault && b.isDefault) || (!a.isDefault && !b.isDefault)) { return a.name.localeCompare(b.name) }else{ return !a.isDefault } }) console.log(objPanoramas); 

Answer 3

You should return positive value, zero or negative from callback of sort :

objPanoramas.sort((a, b) => {
     if(a.isDefault == b.isDefault) {
         return a.name.localeCompare(b.name); //in case both values are equal do alphabetical sort
     } else if(a.isDefault) {
          return 1; //else if a.isDefault is true return positive value.
     }
})

Answer 4

This is exactely what you need:

https://stackoverflow.com/a/4576720/6482090

As you can see into this post the solution is to check both value inside your sort().

Look at the example on that post!