使用Visual Studio 2013和Arduino串行/ COM端口使用C＃关闭Windows 7

Question

I am trying to create a program that will shutdown my system when a specific string or character is sent from my Arduino. When I debug the program and send string "S" from my Arduino, the console application simply closes without a printout.

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.IO.Ports;
using System.Diagnostics;

namespace Arduino_Test
{
class Program
    {
    static void Main(string[] args)
        {
        SerialPort myport = new SerialPort();
        myport.BaudRate = 9600;
        myport.PortName = "COM5";
        myport.Open();

            string data_rx = myport.ReadLine();
            string s = "S";
            if(data_rx == s)
            {
               Console.WriteLine(data_rx);
               var psi = new ProcessStartInfo("shutdown", "/s /f /t 0");
               psi.CreateNoWindow = true;
               psi.UseShellExecute = false;
               Process.Start(psi);
            }
        }
    }
}

I suspect something is wrong within the if statement. Furthermore I am in need of help regarding Visual Studio 2013, I am unfamiliar with C# and the application. My project is a console application, is it possible to create a windows forms application using the same code? I am under experienced in this field and your patience is appreciated.

Answer 1

You will want to define some new terminal state, but lets pretend that it should run forever. If that is the case, simply put your read code in a loop.

while(true) {
        string data_rx = myport.ReadLine();
        string s = "S";
        if(data_rx == s)
        {
           Console.WriteLine(data_rx);
           var psi = new ProcessStartInfo("shutdown", "/s /f /t 0");
           psi.CreateNoWindow = true;
           psi.UseShellExecute = false;
           Process.Start(psi);
        }
}