[英]Execute flask-SQLAlchemy subquery
I want to execute the following subquery in flask-SQLAlchemy but don't know how: 我想在flask-SQLAlchemy中执行以下子查询,但不知道如何:
SELECT *
FROM (
SELECT *
FROM `articles`
WHERE publisher_id = "bild"
ORDER BY date_time DESC
LIMIT 10
) AS t
ORDER BY RAND( )
LIMIT 2
I know I can build the query as: 我知道我可以将查询构建为:
subq = Article.query.filter(Article.publisher_id =='bild').order_by(Article.date_time.desc()).limit(10).subquery()
qry = subq.select().order_by(func.rand()).limit(2)
However I don't know how to execute it in the same fashion as I would execute eg 但是我不知道如何以与我执行相同的方式执行它,例如
articles = Article.query.filter(Article.publisher_id =='bild').all()
ie to get all the Article objects. 即获取所有Article对象。 What I can do is call 我能做的就是打电话
db.session.execute(qry).fetchall()
but this only gives me a list with actual row values instead of the objects on which I could for example call another function (like article.to_json()
). 但这只给了我一个包含实际行值的列表,而不是我可以调用另一个函数的对象(如article.to_json()
)。
Any ideas? 有任何想法吗? qry
is a sqlalchemy.sql.selectable.Select
object and db.session.execute(qry)
a sqlalchemy.engine.result.ResultProxy
while Article.query
, on which I could call all()
, is a flask_sqlalchemy.BaseQuery
. qry
是一个sqlalchemy.sql.selectable.Select
对象和db.session.execute(qry)
一sqlalchemy.engine.result.ResultProxy
而Article.query
,关于这一点我可以调用all()
是一个flask_sqlalchemy.BaseQuery
。 Thanks!! 谢谢!!
You can use select_entity_from 您可以使用select_entity_from
qry = db.session.query(Article).select_entity_from(subq).order_by(func.rand()).limit(2)
Article.query.filter(Article.publisher_id =='bild')\
.order_by(Article.date_time.desc())\
.limit(10)\
.from_self()\
.order_by(func.rand())\
.limit(2)
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