Grep文字仅在[word]之后：

Question

I have a file example.txt which contains following text:

[one]: bla bla bla onebla twobla
[two]: hey heya noheya
[onemore]: i got mad and etc

I need to grep and show only text that after [myword]:

Tried to test grep [myword] /tmp/example.txt | cut -d ':' -f 2 grep [myword] /tmp/example.txt | cut -d ':' -f 2

On each [myword] it prints all after brackets, but how can I get only the one I need only and not all?

Answer 1

You can cut the first phrase [something]: and get the rest using

grep and sed:

$ grep -w "\[onemore\]:" words.txt | sed 's/\[onemore\]://g'
 i got mad

grep and awk:

$ grep -w "\[onemore\]:" words.txt | awk -F: '{print $2}'
 i got mad

Answer 2

Thanks to all! Got an answer on other from Unix & Linux:

$ awk '/\\[myword\\]/{sub(/^[^]]*\\]:[[:blank:]]*/,"");print}' example.txt

OR

$ awk '/\\[myword\\]/{sub(/^[^]]*\\]:[[:blank:]]*/,"");print}' example.txt