[英]Why does this conversion give an error?
I have this code in eclipse: 我在eclipse中有以下代码:
String A = String.valueOf(a);
String B = String.valueOf(b);
String C = String.valueOf(c);
String D = String.valueOf(d);
String E = String.valueOf(e);
String F = String.valueOf(f);
String G = String.valueOf(g);
String H = String.valueOf(h);
String I = String.valueOf(i);
String J = String.valueOf(j);
String K = String.valueOf(k);
String rawpassword = A+B+C+D+E+F+G+H+I+J+K;
int password = Integer.parseInt(rawpassword);
System.out.println(password);
And it gives me this error 这给了我这个错误
at java.lang.NumberFormatException.forInputString(NumberFormatException.java:65)
at java.lang.Integer.parseInt(Integer.java:495)
at java.lang.Integer.parseInt(Integer.java:527)
at com.jakibah.codegenerator.Main.Generate(Main.java:65)
at com.jakibah.codegenerator.Main.run(Main.java:24)
at java.lang.Thread.run(Thread.java:745)
But I do not understand why. 但是我不明白为什么。 can someone help me?
有人能帮我吗?
String A = String.valueOf(10);
String B = String.valueOf(10);
String C = String.valueOf(10);
String D = String.valueOf(10);
String E = String.valueOf(10);
String F = String.valueOf(10);
String G = String.valueOf(10);
String H = String.valueOf(10);
String I = String.valueOf(10);
String J = String.valueOf(10);
String K = String.valueOf(10);
String codestring = A+B+C+D+E+F+G+H+I+J+K;
BigInteger bigInteger = new BigInteger(codestring);
System.out.println(bigInteger.max(bigInteger));
The parseInt(String s)
method throws a NumberFormatException
if the argument is not a parseable Integer
. 如果参数不是可解析的
Integer
则parseInt(String s)
方法将引发NumberFormatException
。
Make sure the String
you pass to the method is a Number
and is between -2^31
and 2^31 - 1
确保您传递给该方法的
String
是一个Number
,并且介于-2^31
和2^31 - 1
之间
Number Format exception arise when you trying to convert a string type into a integer but that does not fit as a integer. 当您尝试将字符串类型转换为整数但不适合整数时,会出现“数字格式”异常。 From your code I am not able to understand what value is a,b,c,d,.. From my experience I have uploaded two image to show you may be this kind of error you done
从您的代码中,我无法理解a,b,c,d ,.是什么值。根据我的经验,我上传了两张图片以显示您可能是这种错误
here number format exception arise as codestring is 10.320 and it is a string type so when compiler try to convert it as a string it unable to convert it due to . 此处出现数字格式异常,因为代码字符串为10.320,并且它是字符串类型,因此当编译器尝试将其转换为字符串时,由于不能转换。
But in this scenario codestring is 1020 , so easily it convert to a int. 但是在这种情况下,代码字符串为1020,因此很容易将其转换为int。
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