[英]PHP Trying to get property of non-object error in function
Need some help please. 请需要帮助。 I am getting a 'Trying to get property of non-object' error in a function call that looks at an array.
我在查看数组的函数调用中遇到“试图获取非对象的属性”错误。
The array I am calling is 我正在调用的数组是
$var = array(
"variableA" => "abc123",
"variableB" => "123456789"
);
The function I am using is 我正在使用的功能是
public function getJson($var)
{
$resource = sprintf("/info/%s/%s/json", $var->variableA, $var->variableB);
return $this->_restCall('GET', $resource);
}
I cant understand why the array values are not being passed through? 我不明白为什么数组值没有通过?
Could someone please help? 有人可以帮忙吗?
$var
is an array not an object. $var
是一个数组,不是对象。 So you need to use array syntax, not object syntax: 因此,您需要使用数组语法,而不是对象语法:
public function getJson($var)
{
$resource = sprintf("/info/%s/%s/json", $var['variableA'], $var['variableB']);
return $this->_restCall('GET', $resource);
}
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