JavaScript修剪字符

Question

I want to delete "()" from each value. How would I do that?

var arr = ["(one)","(two)","(three)","(four)","(five)"];

for(var i = 0; i < arr.length; i++){
  console.log(arr[i]);
}

Answer 1

Since all the other answers are unnecessarily complicated, here's a simple one:

arr = arr.map(s => s.slice(1, -1));

You can do it in-place too if you prefer; the important part is .slice(1, -1) , which takes a substring starting from the character at index 1 (the second character) and ending before the last character ( -1 ).

String.prototype.slice documentation on MDN

Answer 2

use replace

var arr = ["(one)","(two)","(three)","(four)","(five)"];
for(var i = 0; i < arr.length; i++){
var x = arr[i];
x = x.replace(/[()]/g,"");
console.log(x);
}

note:
i dedited, because alexander was right

so u need to use regex, "g" for search globally,
"[" "]" to find all character inside

Answer 3

var arr = ["(one)","(two)","(three)","(four)","(five)"];
for(var i = 0; i < arr.length; i++){
    var arrLength = arr[i].length -2;
    var shortArr = arr[i].substr(1,arrLength);
    console.log(shortArr);
}

This gets one character less on the front and back

Answer 4

This matches ( followed by anything that isn't ) followed by ) . Would also fail for "(test(ing)123)", (if you care)

var arr = ["(one)","(two)","(three)","(four)","(five)"];
for(var i = 0; i < arr.length; i++) {
    arr[i] = arr[i].replace(/\(([^)]+)\)/g, "$1");
}

This is much more simple/faster (but arguably more brittle):

var arr = ["(one)","(two)","(three)","(four)","(five)"];
for(var i = 0; i < arr.length; i++) {
    arr[i] = arr[i].substr(1, arr[i].length - 2);
}

Answer 5

这是快速的，并且无论字符串中有多少个括号都应该起作用，它将全部删除。

arr[i] = arr[i].split(/\(|\)/g).join("");