[英]Update table based on subquery with if condition
I want to achieve something like this: 我想实现以下目标:
update bill b set b.isPaid = (if(select count(*) from bill_payment p where p.bill_id = b.id) > 0,true,false);
but I get this error: 但是我得到这个错误:
ERROR 1064 (42000): You have an error in your SQL syntax; 错误1064(42000):您的SQL语法有错误; check the manual that corresponds to your MySQL server version for the right syntax to use near 'select count(*) from res_bill_payment p where p.bill_id = b.id) > 0,true,false)' at line 1
在第1行上,检查与您的MySQL服务器版本相对应的手册以获取正确的语法,以在'res_bill_payment p中选择count(*),其中p.bill_id = b.id)> 0,true,false)附近使用
How can I do it in mySQL? 如何在mySQL中执行此操作?
I would suggest writing this using EXISTS
: 我建议使用
EXISTS
编写此代码:
UPDATE bill b
SET b.isPaid = (EXISTS (SELECT 1
FROM bill_payment p
WHERE p.bill_id = b.id
)
);
The EXISTS
clause returns a boolean, so there is no need to explicitly use TRUE
and FALSE
(unless you really, really want to). EXISTS
子句返回一个布尔值,因此无需显式使用TRUE
和FALSE
(除非您确实非常希望使用)。
I strongly recommend using EXISTS
instead of COUNT(*)
for this purpose, because it often has much better performance. 我强烈建议为此目的使用
EXISTS
而不是COUNT(*)
,因为它通常具有更好的性能。 EXISTS
can stop at the first matching record, instead of having to count all matching records. EXISTS
可以在第一个匹配记录处停止,而不必计算所有匹配记录。
Seems you are missing some parenthesis: 似乎您缺少一些括号:
UPDATE bill b
SET b.isPaid = (IF(
(
SELECT COUNT(*)
FROM bill_payment p
WHERE p.bill_id = b.id
) > 0
,TRUE
,FALSE
));
UPDATE bill b
SET b.isPaid = true
WHERE
(SELECT count(*)
FROM bill_payment p
WHERE p.bill_id = b.id) > 0;
Would do the trick 会做到的
Or 要么
UPDATE bill b
SET b.isPaid =
(SELECT count(*)
FROM bill_payment p
WHERE p.bill_id = b.id) > 0;
If you want to update EVERY row. 如果要更新每行。
You can also do it with UPDATE..JOIN..
: 您也可以使用
UPDATE..JOIN..
:
UPDATE bill b
LEFT JOIN (SELECT bill_id FROM bill_payment GROUP BY bill_id) bp
ON(bp.bill_id = b.id)
SET b.isPaid = if(bp.bill_id IS NULL , 1 , 0 )
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