如何在DOM体中渲染组件，即使某些其他组件呈现它的反应？
[英]How can I render a component in DOM body even if some other component renders it in react?
问题描述
I have a component, say X which is rendered by my app and in the DOM-body. 
我有一个组件，比如X ，它由我的app和DOM体中呈现。 I have another component Y which is rendered by the component X but the component Y should be opened in full-screen. 我有另一个组件Y ，它由组件X渲染，但组件Y应该全屏打开。 So, I need to render this in document.body rather inside component X even if X renders it. 所以，我需要在document.body渲染它，而不是在组件X即使X渲染它。
React Components' structure is: React Components的结构是：
app
-X
-Y (in Full Screen)
the structure now should look like: 结构现在应该是这样的：
<body>
<div class="X">
<div class="Y">
</div>
</div>
</body>
and the rendered flow should be : 并且渲染的流程应该是：
app.body
-X
-Y
and the DOM structure should be: 并且DOM结构应该是：
<body>
<div class="X">
</div>
<div class="Y">
</div>
</body>
How can I do this. 我怎样才能做到这一点。 Also, I am using ES6 classes for making react-components. 另外，我使用ES6类来制作反应组件。
2 个解决方案
解决方案1
5 已采纳 2016-08-24 13:33:44
UPDATE: Starting from React 16 , there is official support for portals . 更新：从React 16开始，官方支持门户网站 。
Portals provide a first-class way to render children into a DOM node that exists outside the DOM hierarchy of the parent component.
I wouldn't recommend to use this solution as it is using an undocumented React API . 我不建议使用此解决方案，因为它使用的是未记录的React API 。 Disclaimer provided, here it is: 免责声明，这里是：
class Portal extends React.Component { componentDidUpdate() { this._renderLayer(); } componentDidMount() { this._renderLayer(); } componentWillUnmount() { ReactDOM.unmountComponentAtNode(document.getElementById(this.props.container)); } _renderLayer() { ReactDOM.unstable_renderSubtreeIntoContainer(this, this.props.children, document.getElementById(this.props.container)); } render() { return null; } } class Y extends React.Component { render() { return <div>Y</div>; } } class X extends React.Component { render() { return ( <div> X <Portal container="Y"> <Y /> </Portal> </div> ); } } ReactDOM.render(<X/>, document.getElementById('X'));
<script src="https://cdnjs.cloudflare.com/ajax/libs/react/15.1.0/react.js"></script> <script src="https://cdnjs.cloudflare.com/ajax/libs/react/15.1.0/react-dom.min.js"></script> <div id='X'></div> <div id='Y'></div>
解决方案2
1 2016-08-24 12:39:32
Simply render each of your component in their own <div> : 只需在自己的<div>渲染每个组件：
<body>
<div id="app"></div>
<div id="Y"></div>
</body>
And render each component separately: 并分别渲染每个组件：
React.render(ComponentApp, document.getElementById("app"));
React.render(ComponentX, document.getElementById("X"));
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