[英]URL getResource not working when in JAR file
My application loads a txt file which is in PROJECTNAME/resource
folder. 我的应用程序加载了PROJECTNAME/resource
文件夹中的txt文件。
Here is how I'm loading the file: 这是我加载文件的方式:
URL url = getClass().getClassLoader().getResource("batTemplate.txt");
java.nio.file.Path resPath;
String bat = "";
try {
resPath = java.nio.file.Paths.get(url.toURI());
bat = new String(java.nio.file.Files.readAllBytes(resPath), "UTF8");
} catch (URISyntaxException | IOException e1) {
e1.printStackTrace();
}
NOTE: This works when I run from Eclipse, and doesn't when I Export to a Jar file (Extract required lib. into generated JAR). 注意:这在我从Eclipse运行时有效,而在我导出到Jar文件(将所需的库提取到生成的JAR中)时不起作用。 I know that the file is being extracted because its in the JAR file. 我知道该文件正在提取中,因为它在JAR文件中。 Also the images work. 图像也起作用。
Error MSG: 错误MSG:
Exception in thread "AWT-EventQueue-0" java.lang.IllegalArgumentException:
Illegal character in path at index 38: file:/C:/DataTransformation/Reports Program/ReportsSetup.jar
at com.sun.nio.zipfs.ZipFileSystemProvider.uriToPath(ZipFileSystemProvider.java:87)
at com.sun.nio.zipfs.ZipFileSystemProvider.getFileSystem(ZipFileSystemProvider.java:166)
at com.sun.nio.zipfs.ZipFileSystemProvider.getPath(ZipFileSystemProvider.java:157)
at java.nio.file.Paths.get(Unknown Source)
at ReportSetup$13.mouseReleased(ReportSetup.java:794)
I also looked at the similar problem here, however they refer to file/URL outside JAR file. 我在这里也看到了类似的问题,但是它们引用的是JAR文件之外的文件/ URL。
A .jar entry is not a file; .jar条目不是文件; it is part of the .jar archive. 它是.jar存档的一部分。 It is not possible to convert a resource to Path. 无法将资源转换为Path。 You'll want to read it using getResourceAsStream
instead. 您将要使用getResourceAsStream
来阅读它。
To read all of it, you have a few options. 要阅读所有内容,您有一些选择。 You can use a Scanner: 您可以使用扫描仪:
try (Scanner s = new Scanner(getClass().getClassLoader().getResourceAsStream("batTemplate.txt"), "UTF-8")) {
bat = s.useDelimiter("\\Z").next();
if (s.ioException() != null) {
throw s.ioException();
}
}
You can copy the resource to a temporary file: 您可以将资源复制到一个临时文件中:
Path batFile = Files.createTempFile("template", ".bat");
try (InputStream stream = getClass().getClassLoader().getResourceAsStream("batTemplate.txt")) {
Files.copy(stream, batFile);
}
You can simply read the text from an InputStreamReader: 您可以简单地从InputStreamReader中读取文本:
StringBuilder text = new StringBuilder();
try (Reader reader = new BufferedReader(
new InputStreamReader(
getClass().getClassLoader().getResourceAsStream("batTemplate.txt"),
StandardCharsets.UTF_8))) {
int c;
while ((c = reader.read()) >= 0) {
text.append(c);
}
}
String bat = text.toString();
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