从URL解析字符串值

Question

I have a string (which is an URL) in this pattern https://xxx.kflslfsk.com/kjjfkskfjksf/v1/files/media/93939393hhs8.jpeg now I want to clip it to this

media/93939393hhs8.jpeg

I want to remove all the characters before the second last slash / .

i'm a newbie in java but in swift (iOS) this is how we do this:

if let url = NSURL(string:"https://xxx.kflslfsk.com/kjjfkskfjksf/v1/files/media/93939393hhs8.jpeg"), pathComponents = url.pathComponents {
    let trimmedString = pathComponents.suffix(2).joinWithSeparator("/")
    print(trimmedString) // "output =  media/93939393hhs8.jpeg"
}

Basically, I'm removing everything from this Url expect of last 2 item and then.

I'm joining those 2 items using / .

Answer 1

String ret = url.substring(url.indexof("media"),url.indexof("jpg"))

Answer 2

Are you familiar with Regex? Try to use this Regex (explained in the link) that captures the last 2 items separated with / :

.*?\/([^\/]+?\/[^\/]+?$)

Here is the example in Java (don't forget the escaping with \\\\ :

Pattern p = Pattern.compile("^.*?\\/([^\\/]+?\\/[^\\/]+?$)");
Matcher m = p.matcher(string);

if (m.find()) {
    System.out.println(m.group(1));
}

---

Alternatively there is the split(..) function, however I recommend you the way above. (Finally concatenate separated strings correctly with StringBuilder ).

String part[] = string.split("/");
int l = part.length;
StringBuilder sb = new StringBuilder();
String result = sb.append(part[l-2]).append("/").append(part[l-1]).toString();

---

Both giving the same result: media/93939393hhs8.jpeg

Answer 3

 string result=url.substring(url.substring(0,url.lastIndexOf('/')).lastIndexOf('/'));

or

Use Split and add last 2 items

  string[] arr=url.split("/");
  string result= arr[arr.length-2]+"/"+arr[arr.length-1]

Answer 4

public static String parseUrl(String str) {
    return (str.lastIndexOf("/") > 0) ? str.substring(1+(str.substring(0,str.lastIndexOf("/")).lastIndexOf("/"))) : str;
}