[英]Convert a python list having a mix of unicode values and floating numbers
So I am reading values from an excel and storing inside a list. 因此,我正在从Excel中读取值并将其存储在列表中。 But by default, it stored strings as unicode strings and numbers as floats.
但是默认情况下,它将字符串存储为unicode字符串,将数字存储为浮点数。 I want to convert unicode strings into normal strings and float to integer.
我想将unicode字符串转换为普通字符串,然后将其浮动为整数。 How do I do that?
我怎么做?
Here's my list: 这是我的清单:
import xlrd
wb = xlrd.open_workbook("test.xlsx")
firstsheet = wb.sheet_by_index(0)
rows =1
rowvalues = []
while(rows <= (firstsheet.nrows)-1):
rowvalues.extend(firstsheet.row_values(rows))
rows+=1
print rowvalues
Output: 输出:
[121090999.0, 3454554455.0, u'Shantharam', 121090999.0, 5645.0, u'Puranik']
What I need: 我需要的:
[ 121090999, 3454554455, 'Shantharam', 121090999, 5645, 'Puranik' ]
Below is the list
comprehension to convert items in list to: 下面是将
list
项目转换为的list
理解:
str
if it is unicode
str
如果是unicode
int
if it is float
float
,则为int
Sample Example:
范例范例:
>>> my_list = [121090999.0, 3454554455.0, u'Shantharam', 121090999.0, 5645.0, u'Puranik']
>>> [str(item) if isinstance(item, unicode) else int(item) if isinstance(item,float) else item for item in my_list]
# Output: [121090999, 3454554455, 'Shantharam', 121090999, 5645, 'Puranik']
However, instead of converting list to desired format, you should make these checks ( if conditions) at the time you are extending rowvalues
但是,
rowvalues
将列表转换为所需的格式外,您还应该在扩展rowvalues
时进行这些检查( 如果有条件的话)
You can use isinstance to check the type of the variable 您可以使用isinstance检查变量的类型
rows = [121090999.0, 3454554455.0, u'Shantharam', 121090999.0, 5645.0, u'Puranik']
def convert_rows(rows):
for kk,vv in enumerate(rows):
if isinstance(vv,float):
rows[kk] = int(vv)
if isinstance(vv,unicode):
rows[kk] = vv.encode('ascii')
return rows
print( convert_rows(rows) )
# prints [121090999, 3454554455L, 'Shantharam', 121090999, 5645, 'Puranik']
Here is a short script that should do the trick: 这是一个可以解决问题的简短脚本:
l=[121090999.0, 3454554455.0, u'Shantharam', 121090999.0, 5645.0, u'Puranik'];
i=0
for i in range(len(l)-1):
if isinstance(l[i], float):
l[i]=int(l[i])
else:
l[i]=str(l[i])
print(l)
Below is the list comprehension code which does exactly what you want: 下面是完全符合您要求的列表理解代码:
[int(d) if isinstance(d, float) else str(d) if isinstance(d, unicode) else d for d in my_list]
Run this code on your my_list
and you'll get the following response: 在您的
my_list
上运行此代码,您将得到以下响应:
new_list = [121090999, 3454554455, 'Shantharam', 121090999, 5645, 'Puranik']
You can verify the datatype of the elements as: 您可以通过以下方式验证元素的数据类型:
type(new_list[-1]) # <type 'str'>
type(new_list[-2]) # <type 'int'>
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.