Python 自动按键 QtGUI

Question

I have a python script with the section below:

for index in range(1,10):
   os.system('./test')
   os.system('xdotool key Return') 

What I want to do is to run the executable ./test, which brings up a QtGUI. In this GUI, a key press prompt buton comes up. I want to automate this key press of the GUI so that the executable continues.

My python script though runs the executable, the GUI prompt comes up and a key press is not entered until after the executable. Is there any way to fix this?

Answer 1

os.system doesn't return until the child process exits. You need subprocess.Popen . It's also a good idea to sleep a while before sending keystrokes (it may take some time for the child process to get ready to accept user input):

from subprocess import Popen
from time import sleep

for index in range(1,10):
   # start the child
   process = Popen('./test')
   # sleep to allow the child to draw its buttons
   sleep(.333)
   # send the keystroke
   os.system('xdotool key Return')
   # wait till the child exits
   process.wait()

I'm not shure that you need the last line. If all 9 child processes are supposed to stay alive -- remove it.

Answer 2

Please try Pyautogui !

You may find more details here: https://pyautogui.readthedocs.io/en/latest/quickstart.html#mouse-functions

You can also use ClointFusion, which is developed using Pyautogui among other packages. For more details on ClointFusion: https://github.com/ClointFusion/ClointFusion#readme