如果变量为空，则在循环时断开PHP

Question

I have a CSV (attached below) that I am looping through with PHP. 我有一个CSV（附在下面），我正在使用PHP循环。 Note: the Peter entry is missing an Extension number. 注意： Peter条目缺少Extension号码。

How do I break the loop if any $cell (like Extension ) is empty 如果任何$ cell（如Extension ）为空，我该如何打破循环

<?php
echo "<html><body><table>\n\n";
$f = fopen("users.csv", "r");
while (($line = fgetcsv($f)) !== false) {
        echo "<tr>";
        foreach ($line as $cell) {
                echo "<td>" . htmlspecialchars($cell) . "</td>";
        }
        echo "</tr>\n";
}
fclose($f);
echo "\n</table></body></html>";

~ 〜

Forename,Surname,Extension
Jim,Carey,1973
Peter,Robertson,

Answer 1

Try using this - 试试这个 -

<?php
echo "<html><body><table>\n\n";
$f = fopen("users.csv", "r");
while (($line = fgetcsv($f)) !== false) {
    $row = "<tr>";
    $is_empty = false;
    foreach ($line as $cell) {
        if ($cell !== '') {
            $row .= "<td>" . htmlspecialchars($cell) . "</td>";
        } else {
            $is_empty = true;
        }
    }
    $row .= "</tr>\n";
    if ($is_empty) {
        continue;
    } else {
        echo $row;
    }
}
fclose($f);
echo "\n</table></body></html>";
?>

This solution will print the row only if all the fields have value. 仅当所有字段都具有值时，此解决方案才会打印行。 You can use break instead of continue, if you want to break the loop. 如果要打破循环，可以使用break而不是continue。

如果变量为空，则在循环时断开PHP

问题描述

1 个解决方案

解决方案1
3 已采纳 2016-08-29 13:53:13

如果变量为空，则在循环时断开PHP

问题描述

1 个解决方案

解决方案1 3 已采纳 2016-08-29 13:53:13

解决方案1
3 已采纳 2016-08-29 13:53:13